Search Results

Try:
awk '$NF~/\.[0-9]+\./{if(NF>1) {p=$2; s=$0; next} if(p && $1!=p) {print s RS $0; p=x}}' file

Will fail for input:
Florida 13.7.24.25
13.7.24.25
Chicago 13.17.12.5
uchicago
Nebraska
Tennessee 16.13.3.2
99.13.3.2
Frisco 15.35.18.1
Japan
Canada
France 18.55.7.25
18.55.7.25

Good point, thanks! Small adaption:awk 'NR%2 {getline T; X = $NF; sub (X "$", ""); if (T != X && X T !~ /[^0-9.]/) printf "%s %s\n%s\n", X, $0, T}' file
15.235.18.21 No va
15.234.18.21...

Howsoever, assuming awk is acceptable, try:awk 'NR%2 {getline T; if (T != $2 && $2 T !~ /[^0-9.]/) printf "%s %s\n%s\n", $2, $1, T}' file
15.235.18.21 Nova
15.234.18.21
18.66.20.17 Vermont...

Hello seekryts15,

Could you please try following and let me know if this helps you.

cat script.ksh
Post=50
Testlist=`df -hP /tmp | awk 'FNR>1{sub("%",X,$5);print $5}'`
if [[ $Testlist -lt...

Try TMP=$(echo $Post | sort - file | grep -n $Post)
[ ${TMP%:*} -gt 1 ] && echo "there are numbers below the post threshold" || echo "tested good"

Hello seekryts15,

If I understood your requirement correctly then you could try following and let me know if this helps you.

awk -vPOST="$post" '{A[$0]=$0} END{for(i in A){Q=i>POST?i " greater...

Assuming you entered TEST into A, you can precise the filter with
echo "$ln" | grep -q "/${A}/" ...

Did you consider 'SYS.TLOCK.* TEST$' as the pattern? The $ sign indicates the line end.

Hi, try double quotes instead of single quotes, otherwise $A does not get resolved:
find /home/testuser -name "$A*canvasON.txt"

By changing:
TESTSTATUS=`ps -ef | grep test | grep -v grep | sed -e 's/^[ \t]*//'`

echo
echo
echo "\033[1;37 \033[1mAs soon as Test processes comes back up it will appear below:\033[0m\n"
...

Your loop will never finish as TESTSTATUS will not change its state as it's not reassigned.

Variable expansion does not happen inside a quoted here document.

I don't think it is a good idea to throw away diagnostic messages from ex. If you just don't want to see the informative messages...