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What is the "done" for? Is this an extract from another script with a loop?

kill -9 `ps -ef | grep test.sh | grep -v grep | awk '{print $2}'`
stat=$?
if [ $stat -eq 0 ]
then
echo " script killed at $(date +%D@%T) "
else
echo " script process does not exists...

i have splitted your kill command and see what happens..

see what variable a holds in it ??

# a=`ps -ef |grep /usr/sbin/cron | grep -v grep`
# echo $a
root 438 1 0 Oct 20 2 g 0:02...

Have you tried something like:
echo kill `ps -ef |grep test.sh| grep -v grep`to see what arguments you are passing to kill.
Or even sh -x badscript?

If I would have to guess ... you are running...

Alright, so I was curious how to do this in bash, having never myself attempted it. It's a bit tricky.

First, you can do the operation directly using "Arithmetic Expansion", ie $(( ... ))

$...

You cannot use bourne shell alone to do that. bash has bitwise operators as builtins.
You will have to resort to another interpreted language like perl, or a compiled language like C, if you cannot...

depending on your definition of a 'word' - YMMV...

sed 's# +#,&#g' myFile

Here are a couple of Perl one-liners -


$
$ cat f41
The quick brown fox jumps over the lazy dog.
Mary had a little lamb.
Humpty Dumpty sat on a wall.
$
$
$ perl -plne 's/(\w+)/$1,/g' f41...

Since you are using a while loop, try this...

#!/bin/bash

i=1
while read line
do
test $i -eq 1 && ((i=i+1)) && continue
echo $line
done < infile


Using AWK

awk...

Easiest way is to use sed:


sed 1d $rpt | while read d
do
echo $d
done


The 1d causes the first line to be deleted and sed writes the rest to stdout.

You can save the argument which is being passed to script B in a file everytime script A gets executed.

Here is an example.


Script A

LOC="Where you want to save the argument counter...

$ echo trousers:shirts,price,50 | awk -F"," '{print $3 " " $1 "." $2}'
50 trousers:shirts.price


Instead of an echo, you could pass the input file to that awk command.

This will get you the 5th line
sed -n 5p infile

To check for "string" in 5th line:

awk 'NR==5&&/string/ {exit 1}' infile || echo "Found it!"

What Operating System(s) are you running? Please be specific and detail any additional packages or other hooks which you may have installed. There is no way that a standard M$ Windows at any version...

$ echo ${mask#2#} | awk '{for(i=1;i<=NF;i++)if($i)print i-1}' FS=
0
13
24
30But shouldn't the position be determined from right to left?
$ echo ${mask#2#} | awk '{for(i=NF;i>=1;i--)if($i)print...

Oh ! ... i never noticed this before
~ is described as "Bitwise not" in oreilly ksh book ... but it is not the behaviour i see, xor 1 should be used instead

$ echo $SHELL
/bin/ksh
$...

OK if you have gawk and ksh:

$ cat bits.awk
#!/bin/ksh
echo $1 | gawk --non-decimal-data ' {
for(i=lshift(1,31);i;i=rshift(i,1))
printf "%d%s", (and(("0x"$1)+0,i) > 0), ++c%4==0?" ":"";...

If your Korn shell is a recent version of ksh93, try the following

#!/bin/ksh93

integer -i2 mask=16#F0000000
integer -i2 v0 v1 v2 v3 v4 v5 v6 v7

read hn?"Enter a 32-bit hex decimal number:...

Why not put the bits in an array? (you will probably find them easier to work with in your script later):

$ eval B="( $(echo 1000000000000100000000001000001 | sed 's/./& /g') )"

$ for ((i=0;...

$ echo "1000000000000100000000001000001" | sed 's/ */ /g;s/^ //;s/ $//' | tr ' ' '\n' | cat -n |sed '/0$/d;/1$/s/^[[:blank:]]*/b/;s/[[:blank:]]1/=1/'
b1=1
b14=1
b25=1
b31=1
$

If you have gawk and bash:

$ cat bits.awk
#!/bin/bash
echo $((16#$1)) | gawk ' {
for(i=lshift(1,31);i;i=rshift(i,1))
printf "%d%s", (and($1,i) > 0), ++c%4==0?" ":"";
printf"\n"; }'

$...

$ cat hex2bin.awk

BEGIN {
FS=""
a["f"]="1111"
a["e"]="1110"
a["d"]="1101"
a["c"]="1100"
a["b"]="1011"
a["a"]="1010"
a["9"]="1001"
a["8"]="1000"
a["7"]="0111"
a["6"]="0110"...

simple example using bc. parse the output into whatever you want

$ bc <<EOF
> ibase=16
> obase=2
> FFFF
> EOF
1111111111111111

I think the first question is what scripting language do you wish to use?