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my @arrayline=`ssh -n $user\@$server $cmd`;above code connects to server whose user name is $user, server address is $server.
and executes command $cmd and assign the output to your variable..

Would like to add to above :

It will select all the elements from @filelist that contain "$cutomers" and replaces @filelist with that new list.

Value referred by $seen{$_} is incremented, and the elements from @in that doesn't contain new $seen{$_} is picked and stored in @unique.

Read about grep in perldoc...

Yes. See Regexp Quote-Like Operators in perlop.

The substitution command replaces first part with second part s/first_part/second_part/. The 'g' flag is to apply the substitution many times for...

Hi,

Just check wheather the variable have value greater than or equal to zero then its positive else negative.

if ( $max >= 0 )
{
print "Positive\n";
}
else
{
print "Negative\n";
}...

Hi,

Try this one,


$new_dates =~ s/\s+//g;


Cheers,
Ranga:)

You understood the substitution right...
s/yyyy/$Y1
Replace yyyy with the value of $Y1

$_ is a inbuilt variable. So if we do any operations without specifying the variables, it will be done on...

The nine element array created by localtime, for example, can be concatenated or printed in any order. The date value requires + 1900 to get the year, and the month is zero-based and requires +1 to...

Numerical and string comparisons require different operators.

This is from perldoc perlop:

You need:

$date_var ne ''

instead of:

$date_var != ''

Change all the %H in %I in order to provide valid dates to the date command.

It should handle AM/PM correctly. Try it and let us know.