Search Results

Hi,

In awk all variables are initiated with a default value, which is "", and is equal to 0 in a numeric context.

On the first line the value for max is equal to this default value, and so...

May I jump in as Don seems offline for a while now?'


sed operates on files line by line, it reads a line, performs the entire script on it, and reads the next. * is not "all lines" but a sort...

Hi nag_sathi,
It looks like RudiC answered the question for you while I was sleeping last night. Do you still have questions about how that sed search command works?

Note that the ability to use...

Further notes:

The backslash serves no purpose here, you can leave it out.
There should be double quotes around the variable expansions "$file" "${file%.*}"
It is best to put -- (end of...

Hello nag_sathi,

This is called "parameter expansion" see following from documentation.



Here is the link for understanding parameter expansion too.
Shell Parameter Expansion (Bash...

Yes, that's a "Parameter Expansion / Remove matching suffix pattern".


man bash:

You never answered the question of whether a file named filexfile.txt should be moved to newfilexfile.txt or to newfilexnewfile.txt. And, I'm disappointed that you didn't try to rewrite your code...

Try something like:

for i in ~/Shell_Practice/rename/*.txt
do
if [ -e "$i" ]; then
mv -- "$i" "${i/file/newfile}"
fi
done

or
shopt -s nullglob
for i in...

The necessary modifications to your own loop were presented to you, to make it run, and to improve it. However, no sed nor awk are needed to solve your problem. Just use shell's "parameter...

Hello Nag_sathi,

Following command may help you in same. It will delete the files older than 90 days with name


find . -type f -mtime +90 -name "tomcatfiles*.log" | xargs rm -rf


Also...

There is no need to start up xargs for this. The following does the same thing without invoking xargs:
find . -type f -mtime +90 -name 'tomcatfiles*.log' -exec rm -f {} \;

Please specify what exactly you mean by "3 month old":

exactly 3 months/90 days?
3 months/90 days and older?
3 months / 90 days and younger?

The command you wrote:

find . -mtime +90
...

Better to use -exec operator.

First use this for verification:
find . -type f -mtime +90 -name 'tomcatfiles*.log' -exec ls {} \;

And then this for deletion:
find . -type f -mtime +90 -name...

In linux, you should have a tool like unix2dos available. Try to apply this and report back.

You will find it under /var/spool/cron

Taking the command apart we get...

WORKFLOW_START_TIME=$(..) #assign the output of the contained command to WORKFLOW_START_TIME
perl -e # execute the following string under the perlinterpreter...

Horrible, but it works...

WORKFLOW_START_TIME=$(perl -e '@t= localtime(time() + (5 *(60 * 60 )));printf "%02d/%02d/%04d %02d:%02d:%02d\n", $t[4] + 1, $t[3],$t[5]+1900, @t[2,1,0]')

Please check my previous post.

I have corrected in the script.

I believe line is a variable you have used.
better way you just assign it to variable. You are creating a file with > sign.

try

line=$(echo $line | tr '[:upper:]' '[:lower:]')or with awk...

You do realize that when you change the content (upper to lower is changing content) you break the decompression algorithm: meaning you can no longer reliably decompress the file correctly - you get...

You should use only parentheses or back tics, not both
st_date=$(`date "+%Y%m%d"`)

Best
st_date=$(date "+%Y%m%d")

ok
st_date=`date "+%Y%m%d"`

Edit: I now see that its ok in the full...

Is that your full script? Error says line 8 and your code is in line 4.

I would advise to you to start use of functions in the script.

while [[ ! -f "$file" ]]; do
if [[ $lc -lt 15 ]]
then
sleep 15 # this should 60 as it is in seconds
let lc=lc+1
print...

Hi,
grep search pattern "ORA-" in status.log file and redirect the stdout to /dev/null
2>&1 mean redirect stderr to stdout,in your case stdout is already redirected to (output of grep command)...

$# represents the number of arguments:


$ set -- a
$ echo $#
1

$ set -- a b c
$ echo $#
3