Search Results

find . -type f -exec grep -l "osuser" {} \; | xargs grep -l "v$session"

Try using the below code :


find . -type d -exec ls -ld {} \; | awk '{print $3,$9}' | grep -v oasitqtc

It should give you desired output

However better code will be with egrep as states...

Unnecessary to use grep with awk:
find . -type d -exec ls -ld {} \; | awk '$3 != "oasitqtc"{print $3, $NF} '

I assume "/apps/qtcdev/appl_top" is your APPL_TOP? Then use: find /apps/qtcdev/appl_top -type d -name "xx*" -a ! -name "xxk*" | xargs -i find '{}' -type d ! -perm 777 Path to search always comes...

RULES OF THE UNIX AND LINUX FORUMS

For the latest version of the community rules (the official community rules page), please visit here. (https://www.unix.com/misc.php?do=cfrules)


No flames,...