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The awk system() function returns the exit code of the command that it executes; not the output produced by that command. Unless your input is coming from a slow running pipeline (which is not the...

Borrowing from Don:

awk -F, -v date=$(date '+%Y%m%d%H%M%S') 'FNR>1{$6=date}1' OFS=, final_copy.csv

Try awk -F "," 'BEGIN{ OFS=","; cmd = "date '+%Y%m%d%H%M%S'"} NR>1 {cmd | getline $6; close (cmd)} 1' file

ls=$(cal | awk '$1+=0 {ls=$1} END {print ls}')
ts=$(date +"%d")

[[ $ls = $ts ]] && echo "today is the last sunday of the month"

Hello netdbaind,

Following may help you in same.
Let's say following is cal.


cal
October 2014
Su Mo Tu We Th Fr Sa
1 2 3 4
5 6 7 8 9 10 11
12 13 14 15 16 17 18...

How about cal | awk 'NR==3 {print 15+NF%7}'
19
And, if you run it on every Sunday, you can check if date +"%d" is between 15 and 21.

Hello netdbaind,

I agree with vbe's solution like we can run script on each Sunday and check either it is 3rd Sunday or not.
Following code may help you to get the 3rd Sunday with explaination....

$ sed -n '1p; /Network/p' file
Filesystem Size Used Avail Use% Mounted on
4.0T 523G 3.5T 13% /Network/Test
$ awk 'NR==1 || /Network/' file
Filesystem ...

to=$(date -d "2013-02-12 11:46:40.197045" +%s)
from=$(date -d "2013-02-11 00:46:40.389037" +%s)
echo $(( $to - $from ))

You can use
Integer
F=$(($E/$S))

Non integer
F=$(echo $E $S | awk '{print $1/$2}')
58.9564

When dealing with non-integer numbers I'd recommend to use bc instead of expr.
$ E=1296863.27001857757568359375
$ S=21997
$ F=$(echo "$E / $S" |bc)
$ echo $F
58
$ F=$(echo "scale=20; $E / $S"...

sort <filename> | tail -1

sort -n filename | tail -1

One way of many to do this:

Part A.
create a list of script files with full script files names: e.g., /path/to/script.sh
Next use that list to create a file with checksums

while read fname ...