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Hi Scrutinizer,
Thanks Scurtinizer, thanks for your advice.
\{1,\} is not nessesary, a [[:blank:]] is totally enough, the sed code is better after you edited it.

Awk approach with fixed strings:
awk '$1=="b" && k=="a" {print p ORS $0}{p=$0; k=$1}' file


--
@lucas: nice sed. \{1,\} can be left out, no?


*edit* it could also be done like this.
sed...

Hi guy,
Try this:
sed -n '/^a[[:blank:]]\{1,\}/{N;/\nb[[:blank:]]\{1,\}/p;D}'

cheers.

This is a fairly simple awk script. Here it is again with comments explaining what each line does:
awk '
$1 == f1 || NR == 1 { # If the 1st field is the same as the 1st field on the
...

Yes, one of those lines is it. If you change:
f0 = "" # Clear the saved line. (We do not want to print
# the current line twice if the 1st...

As per desired output.. with sum sorted in descending order.
perl -ane '$x{$F[0]}+=$F[1];$y{$F[0]}++; END{%x=reverse %x;print "$x{$_} $_ $y{$x{$_}}\n" for(reverse sort{$a<=>$b} keys %x)}' inputfile

Try this:
awk '{a[$1]+=$2;b[$1]++}END{for(i in a)print i, a[i], b[i]}' file

awk -F "" ' # set Field Separator to null to split the letters.
NR==FNR{a[NR]=$0;next} # read the first file (file1) into array a , array index is line...

Yes,
I just wanted to show that you can post increment and check with a single expression :)

I believe command in post #3 is doing the same.
@radoulov, a shorter/better command.

Or even:

awk '!_[$2]++' infileTo the OP: please elaborate more on how the output from anurag.singh's (https://www.unix.com/members/302086885.html) command is wrong.

awk '{if(!a[$2]) print;a[$2]++;}' inPutfile

Try: perl -pe 'BEGIN{open O, "reference_file_1"; chomp(@a=<O>)} for $i (@a){$x="X" x length($i);s/$i/$x/g}' target_file > output_file

Firstly this seems remarkably close to one of your many threads on this subject except that it has three files not two files....

Franklin52's idea is much better.
You do not really have to check if the first 3 or last 3 characters are non-X. The result is code brevity.


$
$ cat f25
>Read_1
XXXXXXXXXXABCXXXXXXS...

awk '
/^..X/{sub("^..X","XXX")}
/X..$/{sub("X..$","XXX")}
1' file

Not sure what you mean by "idea to archive it" - I don't see anything about archiving in your post. You probably mean "achieve it".

In any case, the script that follows takes care of the case...

sed 's/X[^X]X/XXX/g;s/X[^X][^X]X/XXXX/g;s/X[^X][^X][^X]X/XXXXX/g' input >output

perl -pe 's/X[^X]X/XXX/g;s/X[^X]{2}X/XXXX/g;s/X[^X]{3}X/XXXXX/g;' input

split the input data files to small files, and run the same awk command in different console.

then attach them again.

split input.data ABC

nohup awk -f command.awk referral.data ABCaa...

awk -F "" '
NR==FNR{a[NR]=$0;next}
!/>/ {
split(a[FNR],b,"");
{ for (i=1;i<=NF;i++) {printf ($i!=b[i])?b[i]:" "}
printf RS
}
}
' file1...

awk '
NR==FNR {t=$0;gsub(/./,"x");a[t]=$0;next}
{
for (i in a) if ($0~i) sub(i,a[i])
}1
' referral.data input.data

>sample_1
SDFDSKLxxxxxxxxxxxxDSFAS

>sample_2...

$ awk -F "" '
NR==FNR{a[NR]=$0;next}
!/>/ {
split(a[FNR],b,"");
{ for (i=1;i<=NF;i++) {if ($i!=b[i]) printf b[i]}
printf RS
}
}
'...

Another approach:
awk '{printf("%s%s\n",r,$1);r=ORS;$1=""} {
for (i=1;i<=length;i+=6) {
print substr($0,i,6)
}
}' RS= OFS= file

awk '/>/||/^$/ {print;next} {printf $0}' infile |awk 'BEGIN{FS=OFS=""}! />/ {for (i=1;i<=int(NF/6);i++) $(i*6)=$(i*6) RS}1'