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Here, it should not be value "keyword1" is equal to "8" by example...

Regards.

I don't know what you mean Disedorgue. My script does not compare "keyword1" to "8"
I added the output of the command in my post, which is what the OP required.

awk -f oo.awk myFile, where oo.awk is:

BEGIN {
FS=OFS=","
f2r=10
split("24,8,0",fA,FS)
split("Keyword1,Keyword2,Keyword3", fAr,FS)
}
FNR>1{
for(i=1; i in fA;i++)
if ($f2r ==...

Try:
awk '$10==24{$10="keyword1"} $10==8{$10="keyword2"} $10==0{$10="keyword3"}1' FS=, OFS=, file
Col1,Col2,Col3,Col4,Col5,Col6,Col7,Col8,Col9,Col10,Col11,Col12,Col13,Col14,Col15,Col16,Col17...

Hi, try:
awk -F, 'BEGIN{OFS=FS;A[0]="keyword3";A[8]="keyword2";A[24]="keyword1"};A[$10] ? $10=A[$10] : 1' input.txt

Regards.

Similar to Scott's approach, but using Associative Arrays (https://en.wikipedia.org/wiki/Associative_array) in KSH93:
#!/bin/ksh

typeset -A ARR
while read line
do
(( ARR["$line"]++ ))...

$ awk '{
A[$0]++
}

END {
for( a in A )
printf "%-40s : %5d\n", a, A[a]
}' file1
Back-end User state is invalid : 2
Back-end Invalid Id Password : 9...

Another one:
awk 'NR==FNR{a[$1]=$2;next}{FS="@";$4=a[$4]}1' OFS="@" match_log.txt All_service.txt

This should work (but I'm writing it from top of my head, without access to machine with AWK or Linux/Unix):cat match_log.txt | tr -s " " | awk -F"@" 'NR==FNR{split($0,a,"...

#!/usr/bin/env ruby
h={};h.default=""
File.readlines("file").each{|v| g=v.split;h[g[1]]=g[0] }
File.open("file1").each do |line|
sp=line.split("฿")
h.has_key?(sp[1]) and...

This should do the job (strange separator)
#!/bin/bash
IFS='฿'
while read A B C
do
D=$(grep -m1 $B 'My match data.log' | cut -d' ' -f1)
echo "${A}฿${D}฿$B฿$C"
done < 'My log.txt'

awk '
NR==FNR{a[$2]=$1;next}
{
split($0,b,"฿")
if (b[2] in a) sub(b[2],a[b[2]]"."b[2])
}1' date.log log.txt