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Your first attempt works if "\n" is a literal string within your file:
$ cat test1
one two|\nmore
another line
done|\n
$ awk '{ sub(/\|\\n/, "\\n"); print }' test1
one two\nmore
another line...

I would take a look at test statements [ .. ] in your shell script. Probably you left out a quote or forgot to put spaces around the [ and ] or around the = .

You mean like this:
awk 'length>=L{riadok=(length==L?riadok RS:x) "Output: " q FILENAME ":" FS FNR FS length FS $0 q} length > L{L=length}END{ print riadok}' q="'" "$@"

You can use FILENAME and FNR for that:
awk 'length>=L{riadok=(length==L?riadok RS:x) "Output: " FILENAME FS FNR FS length FS $0} length > L{L=length}END{ print riadok}' "$@"

Of course it didn't read stdin. You did not provide anything on stdin. You would need for example a pipe to do that, like I did with the cat example.
And what code did you use? The one in...

The awk already does all that it chooses the longest line(s) from all files. I just used cat as an example to generate input on stdin for the shell script, you can use any process there. Inside the...

I a, having a hard time trying to figure out what you are trying to do. You mention using reading standard input, but I see no read statements. Besides that would not even be possible, at least you...

Presuming /usr/local/bin/bash2 exists on your system, this will not work:
if ["$0" -gt 0]
there should be spaces and quotes have no business in a numerical context
if [ $0 -gt 0 ]
But seeing if...

Shell version
maxlength=0
while IFS= read -r line
do
if [ ${#line} -eq $maxlength ]; then
p="${p}
${#line} \"$line\""
elif [ ${#line} -gt $maxlength ]; then
p="${#line} \"$line\""...

awk 'NR==FNR{L=(length>L)?length:L;next} length==L' infile infile

Try this:
awk 'length==L{S[++i]=$0} length > L{L=length; delete S; S[i=1]=$0}END{ for(j=1;j<=i;j++)print L,"\""S[j]"\"" }' infile



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