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We can't guess what command you have on line 188...

The bash shell cannot handle floating point arithmetic. You need to use another utility such as awk or bc do the calculation.

Using awk for example:

$ cat file
1.23
3.45
5.46
6.23

$...

You can do something like this:
echo $var1 $var2 $var3 | awk '{s+=$0}END{print s/NR}' RS=" "

a=3
b=6
ruby -e "puts '%.2f' % Math.sqrt($a * $b)"

Because Bash (and most other shells) don't know any mathematical operations or functions beyond the basic five (add, sub, mul, div, mod). If you need higher level functions, use bc or a different...

"cp" doesn't read from pipe, so the find is useless. What you're doing just amounts to cp *.* /home/dario/Desktop/

Try cp Results*.pdf /home/dario/Desktop/

Or if you're trying to find...

Are you sure? What if some of them have the same name? They couldn't all exist in the same directory.

cp isn't capable of creating directories unless you gave it the -R parameter, so that can't...

you need ruby installed on your system. if you don't have it, use the other solutions.

Many here will not open a zip file.
Paste your desired output here, and put CODETAGS around it to make it easier to read.

Assumes one per line; narrative is "Unzip to stdout the file you want in the zip, piping it to sed, which runs in the print on demand only mode, looking for the URL in an href attribute, either in...

#!/usr/bin/env ruby -Ku
require 'net/http'
require 'uri'
open("file").each do |line|
if line["gps-ntrip.ibge.gov.br"] and line[".zip"]
url = line.scan(/http:.[^>]*zip/)[0]
...

Try this:
sed -n '/zip/ s/.*href=\([^>]*\)>.*/\1/p' file

let is an arithmetic command. Try:
valor=$1

Ran Wireshark (WS) and found out a couple things.


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