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Good point, Don.
I thought executing echo $(pwd) (as it's not a variable, but rather an active function) through ssh on a remote system, would return the output of command pwd from the remote,...

Not quite. The echoed value shown in red above is also from the local shell; not the shell running on serverB.xxx.org. And, in Bourne based shells, the current working directory is stored in the...

As explained, try the other way round. And, set the -x (--xtrace) option on the remote so you can see what happens.

If i get that right:

You have a server onto which you want to log on using a certain user. If you connect from host A you want the user, after logging in, to go to one certain directory, if you...

When I set up pipeline processes using ssh, I always use ssh without passwords by just exchanging public and private key pairs... (a one time setup, but saves a lot of time and effort afterwards)
...

shouldn't it be this way:

workdirremote='/My/Intended/Path/'
sshpass -p password ssh userid@serverB.xxx.org << ENDSSH
cd ${workdirremote}
echo $(pwd)
ENDSSH

It's easiest to simply add a line of code in your home directory .profile file which changes the directory to the directly you wish after you login.

So, just add this to the bottom of your...

Why doesn't it do what you want / need? Where does it fail?

One approach might be to first check for the longest signals and break if matched. My mawk doesn't offer a sort function, so falling back to the *nix sort command piping into an adaption of your...

https://www.unix.com/images/editor/separator.gifI'm afraid I missed the leading counter. Try
awk '
NR > 1 {if (!(a[$3,$4])) {if (a[$4,$3]) {X = $4
...

Another option using sort:

awk '
{
if (!(a[$3,$4]) && a[$4,$3]) {
X = $4
$4 = $3
$3 = X
}
if (!(a[$3,$4])) a[$3,$4]=++grp;
$1=a[$3,$4] FS $1
} 1 ' infile | sort -d

I think you have made a mistake in your desired output based on your sample input.
here's another alternative - a bit verbose, but....
awk -f sen.awk myFile where sen.awk is:

{ g=(($3>$4)?($4...

Try
awk '
{if (!(a[$3,$4])) {if (a[$4,$3]) {X = $4
$4 = $3
$3 = X
...

Hi senhia83,
maybe a little bit faster than your second solution:
awk 'NR==1 {C=NF;Y=$0;Z=$4;next}{X[NR]=$0;print Z,$1"__"$2"__"$3,$4}END{for(i=5;i<C;++i){$0=Y;Z=$i;j=1;while(++j<=NR){$0=X[j];print...

Whatever strategy you choose, according to your expectation, you will get an output file that is near 5 times bigger than your input file.

input file :
rows = 400k
columns = 3000
Total amount...

Interesting idea! Let the filesystem do a part of the sorting, and let ls sort the other parts.
More fine-tuned so ls sorts less:
outdir=./output
mkdir -p $outdir
awk '
NR==1 {
for (i=4;...

rm -rf output
mkdir output
awk '
NR==1 { for (i=1; i<=NF; i++) a[i]=$i ;}
NR > 1 {
for (i=4; i<=NF; i++) print "touch output/\"" a[i], $1 "__" $2 "__" $3, $i "\"";
}
' infile | sh

ls -1...

With your sample data, the following seems to do what you want fairly efficiently:
awk -F// -v OFS="\t\t" '
BEGIN { M = 0
m = 32000
}
FNR == NR {
if((l = length($0)) in pat) {
pat[l] =...

You state that the desired match for the input:
(\\b-[pt22dx]dfdfs/(dsgfspp22dx//[(\pp22dx)-@@----B-@--
is pp22dx instead of pp22 because pp22dx is longer. But why isn't pt22dx just as valid as...

Stealing from and simplifying Don Cragun's approach - try
awk -F// -v OFS="\t\t" '
FNR == NR {l = length($0)
pat[l] = pat[l] DL[l] $0
DL[l] = "|"
...

Hi.

At our shop, we often try to generalize problem solutions, rather than having a number of separate solutions for similar problems.

In this kind of case we created a code gate to handle...

column=5

rm -f *_testcase.csv
(( acol = column - 1 ))
while read line
do
[[ -z "$line1" ]] && { line1=$line ; continue ; }
IFS=, cols=($line)
fl=${cols[$acol]}${yr}__testcase.csv
...

The output is redirected to the respective file, controlled by $5, as requested in post#1. If a new (i.e. not yet registered) $5 shows up in a line, the new file name is constructed in FN[$5], and...

Try also
awk '
NR==1 {HD = $0
next
}

!FN[$5] {FN[$5] = $5 "2016__testcase.csv"
print HD > FN[$5]
}

{print $0 > FN[$5]
}
' FS=","...

Hello senhia83,

Could you please try following and let me know if this helps you(though honestly saying I am not completly sure about your query).

awk -F, 'NR==1{print >...