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%% tells the shell to start looking for the last occurrence of '/' from the end of string and strip off everything (*) from there till the end (this is done by \/*). The last occurrence of '/' from...

host=${parm1%%\/*}
location=${parm1#*\/}

try with below code

list=`ls *.sh`
echo $list | tr -s '\040' '\012'


Cheers
Harish

Quoting "$LIST" will preserve the ls output format:


echo "$LIST"
You could just as easily use ls *.sql, than using grep (except possibly when a very, very large number of files is involved).

Try...shopt -s extglob
ls !(*.*) *.prog

man getoptsRunning the following

#! /bin/bash
while getopts "abc:n" opt; do
case $opt in
a ) a="true";;
b ) b="true";;
c ) c=$OPTARG;;
n...

If not set File, it's nothing => test give error, need argument

File=""
#...
if [ -f "$File" ]


# maybe better testing: File has value and file exist
if [ "$File" != "" -a -f "$File" ]

Ok..Sorry I didn't see your explanation clearly.
in that case you could change the IFS to '"' then set.

something like..

IFS='"'
set -- $@
echo "TO=$1"
echo "CC=$2"
echo "BCC=$3"

...

Creating an archive with tar and then compressing it with another tool like gzip, bzip2, .... is the usual way, yes.

Though there was similar questions already with a solution:...

Try...set -- $my_row
USER_ID=$1
USERNAME=$2

Is this the one you need..?
USER_ID=$(echo $my_row | awk '{print $1}' )
USERNAME =$(echo $my_row | awk '{print $2}' )

You need an empty line to end the MIME header. Also, uuencode is not quite the same as base64. My suggested changes are in red, below:

The above is working for me.
May be your bourne shell is older? There is nothing to do with ksh (the shebang) here since you are invoking script with command line shell. (sh)

try invoking with...

Do you really only want to count files whose names contain a dot?



Don't use ls. The shell will expand the wildcard:


num_files()
{
[ -e "$1" ] && num_files=$# || num_files=0
}
...

To determine shell:

$ ps -p$$

If other than AR_ this should work too:

SOURCE=`echo $file | sed "s/^[^_]*_//;s/_.*//"`

[^0-9] - means there should be no numbers between 0 to 9 appear before and after your filename (570345)

egrep:
F=570345
echo *${F}* | grep -E '[^0-9]$F[^0-9]'
# ls *${F}* | grep -E '[^0-9]$F[^0-9]' # If the previous doesn't work

the second code is good.

coz in first it will not show the desied result though those three file are a single line representation.
but the ls *${F}* is a three line representation of those three...

ls *[^0-9]570345[^0-9]*