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How about
awk 'NR == 1 {L = index ($0, "r") - 1} {T = substr ($0, L); gsub (/./, "& ", T); print substr ($0, 1, L), T}' file
r s ...

Your post headings are somewhat contradictory. If happy with awk and not insist on TCL, try
awk '
NR < 4 {if (NR == 1) ST = index ($0, "p")
for (i=ST; i<=NF; i+=2) P[i] =...

Hello kshitij,

Could you please try following.


awk '
FNR==NR{
if($0~/^[0-9]+/){
++count
}
sum[count]+=$NF
next
}
/^[0-9]+/{
print $0,sum[++var]
next
}
1
' ...

Your input file is not too consistent in its usage of spaces as field separators. It has one or two between fields, one up to six from BOL to $2 if $1 is missing, and zero or one at EOL. That's what ...

I would use capture groups like this:


sed 's/\([0-9]\)[0-9]\([0-9]\)$/\1\2/' infile

Help me out - I see three fields only, not 7. To remove two trailing digits from $3, try
awk '{sub (/..$/, _, $3)} 1' file

The example file only has 3 fields not 7.

awk - remove last two digits from field 3:
awk '{gsub(/[0-9][0-9]$/,"",$3)} 1' infile

sed - remove last two digits on line
sed 's/[0-9][0-9]$//'...

I suggest using a range expression, so that all replacements occur over all lines. Try:
awk '/Umbist_reverse_inst/,/\);/{gsub(/\(\)/,"")}1' list
Also, the parentheses need to be escaped, since they...

A range must span over two (or more) lines.
With a status variable it may end on the same line:
awk '/Umbist_reverse_inst/ {r=1}; r {gsub(/\(\)/,"")}; /\);/ {r=0}; 1' list
If the start pattern is...

That is the case with sed, but with awk it can be on the same line.

$ printf '1 2\n2 3\n3 4\n' | sed -n '/1/,/2/p'
1 2
2 3

$ printf '1 2\n2 3\n3 4\n' | awk '/1/,/2/'
1 2

You could split on newline before doing a foreach like this:

foreach p [ split $var4 "\n" ] {
puts $p
}

Please check your arithmetics for the SUM of pat9.
I can't see where you comply with the specified weight of .25.


Tryawk -F, -vOFS=, '
NR == 1 {
$1 = sprintf ("%-25s", $1)
...

How about
sed -e '/chip top alist/,/));/{/));/ r file2' -e'}; ' file1
Make sure your regex matches the file's contents (it doesn't in port#1)

Try

sed -e '/));/ {p;r file2' -e'}; ' file1

How aboutawk '
FNR == NR {INS=INS DL $0
DL = ORS
next
}
/^memP/ {C = 1
}
C {BRACNT += gsub (/{/,...

$ sed 's/_bbox[^ ]* / /' infile
addfd_mjlala kksks sksks ks
annsns (sksksk ksks )
adnndn_nsns (( jsjsdj sjsj )
malm_dkdm lsls lsl
mdndk_mkmd_dkd [jkssk jsjs[]
ksksk skksk ((jsjsj jsjsj )

...

If there can also be cases where there is no other word following your matched string and you want to remove that as well, you might want something more like:
sed -s 's/_bbox[^ ]* / /' -s 's/_bbox[^...

Which column to refer to ? You have 2nd have 3rd column in your case.

Try :

$ cat file
ahsh,90.82,add,32424,ahha
hhdh,98.89,hdhdh,92728,neha
hshs,you,97.7,hdhdhd,are,a
jsjsj,wonderful,9788,79.9,aheh
ahdh,95.5,girl, 2737,jolll

$ awk -F,...

Or adjusting your original sed script:
sed 's/[9][0-9]\.[0-9]*/width="100" &/g' file

try also:
awk -F, '{f=0; for (i=1;i<=NF;i++){a=$i;if(!f && a+=0)f=i} ; if ($f<100) $f="witdh=\"100\" " $f} 1' OFS=, infile

If i understand, the AND && is an logical and then 1 && 1=1 (1 && 0=0)

Here is a version of the script with comments:
awk '
$1 ~ /^mod[12]$/ {
# If the 1st field on a line is "mod1" or "mod2", note that we need to
# add text to the next line containing ");".
add...