Search Results

awk '!($2 in f2) { f2[$2]=$3; f1[$2]=$1;next} f2[$1] != $3{ print f1[$2] " & " $1 " are not matching for " $2}' myFile

Thank you for testing it for various inputs and posting the Perl version.
I could not find a working Perl 5.10 version to test it, so am unable to reproduce the bug.
However, after searching on...

I noticed a slight error in my original script.

today=$(date +%Y%m%d)
while read quarter start end
do if [ $start -ge $today ]
then
exit
fi
if [ $today -gt $end ]
then
let...

Would this come close to what you need:
for X in 20170805 20170830 20170915 20171005 20171112 20180522
do END=$(date +"%Y%m%d" -d"$X - $(date +"%d" -d$X) days")
for Q in 1 2 3 4
...

Try this function with variable "start of fiscal year" in the first argument, the quarter in the second:
QUARTER() { TMP=$(($1 %10000/100+($2 -1)*3))
printf "%d %d " $2 $((...

# GNU only
# find . -type d -mindepth 1 -maxdepth 1 -mtime +10 -print
# portable
find . -type d \! -name . -prune -mtime +10 -print | sort |
while read dir
do
n=$(
find "$dir" -type f...

sed 's/""|/|/g' < input > output

With awk:
awk '{gsub(/\"[|]/, "|"); gsub(/[|]\"/, "|"); gsub(/\"\"/, "\""); print}' input
With sed:
sed -e 's/"|/|/g' -e 's/|"/|/g' -e 's/""/"/g' input

Another replace is needed if first field can be quoted:

awk '{gsub(/^"/,"");gsub(/\"[|]/, "|"); gsub(/[|]\"/, "|"); gsub(/\"\"/, "\""); print}' input

sed -e 's/^"//' -e 's/"|/|/g' -e 's/|"/|/g'...

Good catch, but still not complete. We also have to worry about quotes in the last field:
awk '{gsub(/^\"|\"$/, ""); gsub(/\"[|]/, "|"); gsub(/[|]\"/, "|"); gsub(/\"\"/, "\""); print}' input
sed...

The skeleton of a different approach:

paste ... | while read ...; do
nohup ... &
nohup ... &
wait
done

Regards,
Alister

---------- Post updated at 07:10 PM ----------...

typeset -i counter=0
typeset prev_param
typeset curr_param

while read in
do
counter=`expr $counter + 1`
modulus=`expr $counter % 2`

if [ $modulus -eq 0 ]
...

What about this different approach?
The example below is for 4 total instances, 2 of them run simultaneously.
i=0; while((i<=4)); do while (( $(pgrep -c myscript) < 2 )); do let i++ ; nohup...

1) Which OS do you run ?
2) So you want your script to take 2 input arguments in format YYYYMMDD, and then, for every day in between these date, it check whether it can find an existing file with...

To know on which unix plateform you are, use the command
uname -a