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I believe awk would be easier. Your logic would be ! ( /^Eat/ && ! /apple/), or, following De Morgan's law:


$ awk '! /^Eat/ || /apple/' input
Drink a soda
Drink an apple juice
Eat an apple...

if [ "$(uname)" == "AIX" ] ; then
ECHO="print -R"
else
ECHO="echo"
fi

$ECHO "some text"

echo will give undetermined results across shells and/or platforms when using special characters. The best way to get predictable behavior is to use printf with a format specifier.
printf '%s\n'...

Hi,
under bash, you have a set parameter to control these:
$ shopt -s xpg_echo
$ echo 'foo\tbar'
foo bar
$ shopt -u xpg_echo
$ echo 'foo\tbar'
foo\tbar
$ echo -e 'foo\tbar'
foo bar
...

sed? What is the pattern on the third line? Otherwise try something like:
sed -n '/===/{N;/===.*\n===/{n;p;};}' file

try this perl solution instead of sed... will depend on the exact pattern..


perl -0pe...

This should work with all sed:
sed '
/^====================/ {
N;/\n====================/ {
N;s/.*\n= Exit/= Exit/
}
}
' file

Both gives me the same result though on cygwin !

$ while read line; do echo "echo "\"This color is $line and will be ready ASAP"\""; done < tmp
echo "This color is yellow and will be ready ASAP"...

With your extra quotes the $line is not inside quotes, giving some vulnerability.
For demonstration, add another line with a * to file1.txt
BTW, Chubler's $(cat file1.txt) is also vulnerable.

Yes, but your xargs tweak deals with that nicely, I just don't like <file1.txt at the front :D

xargs printf 'echo "This color is %s and will be ready ASAP"\n' <file1.txt

Two quotes too many, which would leave the variable unquoted.
while read line; do
echo "echo \"This color is $line and will be ready ASAP\""
done < file1.txt

printf is cool, let's put xargs on top!
<file1.txt xargs printf 'echo "This color is %s and will be ready ASAP"\n':cool:

couple of more options:

sed 's/.*/echo "This color is & and will be ready ASAP"/' file1.txt
printf 'echo "This color is %s and will be ready ASAP"\n' $(cat file1.txt)

while read line; do echo "echo "\"This color is $line and will be ready ASAP"\""; done < file1.txt


with awk

awk '{print "echo ""\"This color is "$0" and will be ready ASAP\""}' file1.txt

Here are the files that you need. My name is Brian.
You should know that so you can add my name to
your assignment when you turn it in.

:D



$ cat ./bingo.sh
#!/bin/bash

if [ $# -lt 2...

That will print the newline at the wrong end of the line, that is why it messes up. One way to achieve this might be:
awk 'NR>1 && !/^\+/{print RS}1 END{print RS}' ORS= file

awk '!/^[0-9]/{ORS=FS}/^[0-9]/{ORS=RS}1' file

Thank you for the help, but as I stated in my first reply - the double quotes caused an error.

sed: 0602-404 Function s/flag1/ cannot be parsed.

There is no error with the single quotes....

The problem is that /bin/ksh apparently does not exist on your system.

Please try the following, assuming it runs on your system:
$ cat file1
word1
word2
word3
$ cat file2
word1
word2 word3...

Here is a KSH script using Associative Arrays for counting words:
#!/bin/ksh

typeset -A word_ARR

while read line
do
for word in $line
do
((...

I forgot to mention that you require KSH93 to support this code.

KSH88 does not support typeset option -a to define arrays.

Well, then, use the -w switch to grep. This then would yield exactly gary_w's result. But I'm not sure that this will work on all grep versions.

Note that RudiC's method counts the word if it is part of another word. I do not know if this is the desired result as the original spec did not get that detailed. Just sayin'.

Using gary_w's files, would this satisfy your needs:
$ grep -of x1.dat x2.dat| sort |uniq -c
3 word1
5 word2
8 word3


---------- Post updated at 12:50 ---------- Previous...

for i in $(cat file1); do echo -n "$i ";tr -s ' ' '\n' < file2| grep -c "$i ";done > temp03


change echo -n to echo.