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Hi

mkdir -p a/b/c

Guru.

Similarly.
who -ms | awk '{print $1"@"$NF}' | tr -d '()'



Note: In post #1 the first echo and the backticks were not needed or desirable.

echo -e "`whoami`\c"; echo -e "@\c"; who -ms | cut -f 2 -d "(" | sed "s/)$//"

You could also do this:
who -ms | awk '{print $1"@"$NF}' | tr -d '()'

Piping your ls output through this should work:


awk '{n=split( $NF, a, "/" ); $NF=a[n]; print}'


The last field is split and n is assigned the number of fields. The last field is then...

[ -d "/path/a valid/path" ] && echo "A directory" || echo "Not a directory"

You can use test to confirm that path exists and is a directory.


test -d "/path/a valid/path" && printf "A directory \n" || printf "Not a directory \n"


Check man test for further test...