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Perhaps try md5sum, e.g...md5sum -t files* | awk 'a[$1]{printf "%s and %s are the same\n",a[$1],$2;next}{a[$1]=$2}'

This will give you the identical files, but no error msg:

md5sum *|sort|uniq -w32 --all-repeated=separate|cut -f3 -d" "

seq 0 365|while read line
do
d=$(date -d "Jan 1 +$line days " +%d%m)
filename=qqss${d}.ddd
if [[ ! -f $filename ]]; then
echo "$filename is not exist"
fi
done

Give this a go (dont think seq is available in AIX either):

#!/bin/ksh
set -A days 31 $(cal 02 $(date +%Y) | awk 'NF{E=$NF}END{print E}') 31 30 31 30 31 31 30 31 30 31

mth=0
for mth_days in...

May be you have to extract the number from the first line :)

I'm really not certain if this is what you're looking for, if it's not please provide a little more info:

#!/bin/sh
start_number=1
current_number=0
errfound=0
errfiles=""


for file in $(ls...