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Homework and coursework questions can only be posted in the Homework & Coursework forum (https://www.unix.com/homework-coursework-questions/) under special homework rules...

What about non-space non-printable characters? Would you consider a file with 2 or more <linefeed> chars a removal candidate although it has two+ empty lines? Or, a <BEL> (0x07, ^G, \a) char?

Hi,

There's no easy way to do what you want to do with find, or at least not based on a simple -type test. As you've previously been advised, an empty file is defined as a file containing 0 lines...

Or let sed do the global "-" substitution:
sed '1{ x; s/.*/NAME COUNTRY_CODE/; p; s/[^ ]/-/g; G; }' test.txt
In line 1, save to H-buffer, put the title, print, substitute all non space with "-";...

sed '1i NAME COUNTRY\n---- ------------' file
NAME COUNTRY
---- ------------
UK 1234
USA 2354
AUS 2253
IND 4256

or
sed -e '1i NAME COUNTRY' -e '1i ---- ------------' file

Print the previous (stored) lines if s[$0] == 4 and the current line for s[$0] > 4
awk '{p=$1; $1=""; pid[$0,++s[$0]]=p} s[$0]==4 {for (i=1; i<=s[$0]; i++) print pid[$0,i] $0} s[$0]>4 {print p,$0}'...

Sorry. Our mistake. Try changing:
if [ grep -q $pattern "$filename" ]; thento:
if grep -q "$pattern" "$filename"; then
You don't need or want to use test (AKA [ ... ]) here; you just want to...

Then, instead of the whole line, compare
only column$2
awk 's[$2]++<4' test.txtor
the whole line($0) but column$1
awk '{x=$0; $1=""} s[$0]++<4 {print x}' test.txt<4 means up to 4 instances are...

I assume you want to run your script from crontab.
You can store the current job name in a file.
Before you do it, compare it with the old file contents; if different then send mail.