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a but convoluted and could be improved, but it's a start.
awk -f alex.awk file1 file2 where file1 is your 'command output', file2 is the other file and alex.awk is:

BEGIN{ new="-new"}
FNR==NR {...

I think the question was about post-processing stderr.
This is not trivial.
The command 2> >( post-command > error.log ) is one method.
There is also the classic { command 2>&1 >&3 | post-command...

Actually the way you presented your problem you were writing into a a file - "error.log". You just happened to redirect stderr to point to that file.

You might picture UNIX processes (running...

I am not sure what exactly you want to do, but in this case you can simply test for the existence of the file(s) and then construct your own error message:

for i in 1 2 3 4 5 6 7 8 ; do
if [...

If you have single lines in a loop you do not need another loop within
for i in {1..8} ; do ls -al file$i 2> >( read line; echo "$(date): ${line}" >> error.log ) ; done
It is more efficient to have...

Perhaps this :

function pr_sum (txt,arr,end, i) {
print txt
for (i in arr)
print i, arr[i] " records"
print end
}


FNR == 1 {
if (NR>FNR) {
pr_sum(file "...

Hi alex2005, see if this adaptation works for you:

function pr_sum (txt,arr,end, i) {
print txt
for (i in arr)
print i, arr[i] " records"
print end
}

FNR == 1 {
if (NR>FNR)...

This is a demonstration longhand using 'eval' OSX 10.12.3, default bash terminal.
It shows how to create a new variable on the fly and how to extract its contents:-
Last login: Mon Feb 13 09:41:28...

Using bash you can try:

declare ${var2}Value01=$(command 01)
declare ${var2}Value02=$(command 02)

or

printf -v ${var2}Value01 "%s" $(command 01)
printf -v ${var2}Value02 "%s" $(command 02)...

I can honestly say I have no idea what you are trying to do.
There are many errors:-
"$var2Value01=$(command 01)"
"$var2Value02=$(command 02)"
Should be:-
var2Value01=$(command 01)...

In addition to what bakunin has already said, please consider the following...

I am having difficulty understanding what you are trying to do. The shell command language defined by the POSIX...

This is correct, but maybe in a different way than you may have thought.

The shell parses the commandline in several distinct steps and one of these steps is the "expansion" of variables - that...

The spacing in your output is inconsistent and it would have helped if you had explicitly stated that you wanted to remove a trailing period, if present, from each word present in lines being joined;...

If you don't mind reversing the order of the output of the two sections of your output and don't mind a random order of reporting of boxes and items missing from boxes, you could try something like:...

Try:-
awk '
/Time_result/ && $3 > 50 {
t_flag = 1
next
}
/SELECT/ {
s_flag = 1
}
/^#/ && s_flag {
...

With awk it looks simpler:
ls -r | awk -F_ '/\.xml$/ && $1!=p1 {print; p1=$1}'

Nice solution RudiC! You can set TZ for your awk process like this:

TZ=GMT-3 awk -F"-" '
...

You're adding arbitrary 17 hours - why should it advance to 100000 next day (unless you are at 170000)?

Tryawk -F"-" '

function strftime(FMT,SECS) {("date \"+" FMT "\" -d@" SECS) | getline...

Building on top of Chubbier_XL's code and incorporating MadeInGermany's suggestion:
awk '
NR > 1 {if (key == ($1 " " $2) && t5 == int(t5) && $5 == int($5) &&
(t5 + 1) == $5) {
t3 = $3...

As long as all of the data in the fields in question are written with a decimal point and one digit after the decimal point, you don't need to look for the decimal point. You could just check if the...

If x ~ ".0$" is to be an integer test, then should be x ~ "\.0$" or x ~ "[.]0$" or better the speaking x==int(x).

What about 27.30, then? I'd prefer the int($5) way.

---------- Post updated at 12:18 ---------- Previous update was at 12:16 ----------



Wasn't the first condition $1 and $2 be the key?

Presumably, besides the condition that column $5 an $6 are integers (technically 27.0 is not an integer, but you seem to mean numbers that end with .0) they should als be only one higher than the...

How about this:

awk 'key {
if (key == $1" "$2 && f5 ~ ".0$" && $5 ~ ".0$") {
t3=$3
t5=$5
next
}
print key,f3,t3,f5,t5
}
{ key=$1" "$2; f3=t3=$3;...

If your find supports -printf, can I suggest this:

find FOLDER[12] -type f -printf "%s_%p\n" | awk -F_ '
BEGIN { print "ID -","VALUE-FOLDER1|","COUNT FOLDER1|", "VALUE-FOLDER2|","COUNT...