Search Results

If I understand correctly, you want to read from the terminal every other time. You can do that with input redirection. Try:exec 3<&0

while read line
do echo "press oprion"
...

modified your code
try
key="phani;ravi;kiran"
number_of_keys=$(echo $key|awk '{print NF}' FS=';')
for (( i = 1; i <= $number_of_keys; i++ ));
do
key=$(echo $KEY_TO_COMPARE|awk -v var=i 'BEGIN {...

Or

key="phani;ravi;kiran"
echo $key | tr ';' '\n' > keys.lst
grep -if keys.lst /home/t.txt > temp.txt

hope this helps :)

grep -if <(IFS=\;; printf "%s\n" $key) file

Use parameter substitution instead. Assuming there are no blank space separated values in key:
key="phani;ravi;kiran"

for k in ${key//;/ }
do
grep -i "$k" /home/t.txt
done > temp.txt

I don't see where AI_DML gets set, but I presume it is an environmental variable.

You can remove the complex echo | awk to be just:-DML_FILE_NAME_ORIG1="${line%%|*}".... or perhaps change the...

Using array is the best option for this requirement.

You could code something like below:
#!/bin/bash

typeset -a table_name
typeset -i c

while read tn
do
(( ++c ))
...

Hi,

Please look at below.

This is what i have imagined so far.(this is just base structure we can modify this if it is as per your requirement.:))

Please do let me correct if am missing...

just one correction needed.. escape sequence for "."

Now try..

awk -F "\\\.mdc\||\\\.mpc\||\\\.mp\|" '{if($0~/Layout\|\$\[\[recor/){s=$0;}
else if($0~/program files\\\\Ab...

I observed above that you have two patterns at the end of the line..

{30001002|XXparameter|!prototype_path|C:\\Program Files\\Ab Initio\\Ab Initio...

As per my observation.. see below...
It is C directory

{30001002|XXparameter|!prototype_path|C:\\Program Files\\Ab Initio\\Ab Initio GDE\\Components\\Transform\\Join.mpc|3|2|Pw$|@{0|}}try this.....

Just find one common line to get the partitions.. And if your common pattern is same it will work for all the patterns..
like Ab Initio 1438 is common for all the partitions.. just find that pattern...

Is this want you want..?


awk -F "\\" '{if($0~/Layout\|\$\[\[recor/){s=$0;}
else if($0~/Ab Initio 1438\\/){split($11,a,".");x++;fn=a[1]x;{print s > fn ;s=""}}
else if(s){s=s"\n"$0}...

still not clear what you want..
In every post your requirement changes...
As per your tried code above..
try this..
awk '/Layout\|\$\[\[recor/{fn="file_"++x} x{print > fn}' file

awk '{if($0 ~ /XXparameter\|Layout\|/){L=$0}else{if(L){if($0 ~ /tag/){t++;s="tag"t}else{m++;s="main"m}{print L>s;L=""}}{print > s}}}' file

For the colouring of lines, I leave this for your exercise. For the first line, you may want to print your colour escape sequences around the a in the print a > fn statement.
For the file numbering,...

I don't understand. As I pointed out before, all the "Layout" lines in your sample are identical. What should be the filename?

WAIT! There's main and tag in the line after the "Layout" line. Try...

I have to emphasize raj_saini20's request to be more specific, as e.g. all the characteristic lines are identical. However, assuming the line containing "Layout" being the separator, this should do...

try this..

awk '{if($0 ~ /XXparameter\|Layout\|/){a++;print > "file_"a}else{if(a){print > "file_"a}}}' file


for your above record two files are created..

$ls file_*
file_1 file_2