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If you want to assign it all to one variable and then use that value in a loop?
Try:
while IFS=/ read v_LstStdCdhId rest
do
if [[ $rest == *CD/39/AT/CDH_BV_ODS* ]]; then
echo...

Try VAR=$(awk -F"/" '/CD\/39\/AT\/CDH_BV_ODS/ {print $1 FS}' Bteq_Xport_GetLstStdViewToBuild__1274.txt) Can't be tested as the input file has not been posted.

awk '{ORS=sub(/\r$/,X)?X:RS}1' filename
The previous solution works with GNU(Linux) sed only. A Unix sed does not have \r.

mute@zbox:~$ sed '/\r$/{N;s/\r\n//}' 4_test.csv
123456
7890AB


I'm usually an awk guy myself but this seemed worthy

gawk '!/\r/{ORS=RS}/\r/{ORS=X}{gsub(/\r/,X)}1' filename

As Don noted earlier, you did not apply my suggestion. Look carefully: the second brace is in the wrong place:

wrong:
done
}
echo "- OUTSIDE WHILE:var:$var"
}

right:
done
...

In the cat ... | while read you should see another pid while doing ps -ef | grep <your script pid>.
Another pid will be subshell pid with your script PID as parent.

For instance :


echo $$...

You did not apply Scrutinizer's suggestion. And, a subshell and a separate process are two distinct things. And, again, the response is exactly the same. Using cat and a pipeline to feed input...

This thread may help you https://www.unix.com/302912242-post1.html

If you do not have a file but a command to be processed in the loop the corresponding construct will be helpful.

Instead of < file use < <( command )

A way to get around this (for demonstration sake, because done < STG_INSTNCE_COMPLTED_01_451_20170112193018.log
is the superior approach to UUOC and there are better ways than using the grep -i...

In the first example, pipe | creates a subshell outside your current shell to execute a loop.
After the while loop is done, var is 0 in your current shell, since the increment was done in...

Hi - I may be missing the point here, but if it is only the first update line that you are interested in, you could simply do the following :-

grep "Update completed" MyLogFile | head -1
Is this...

something along these lines:

awk '
/^UPDATE/ {type=1;next}
type==1 && /Update completed/ { print "Updated rows: " (($4=="No")?0:$4); type=0}
' myFile

Well, I hope I can explain the behaviour adequately, but mayhap the other experts in here may jump in and correct/improve my comments...

shells, when expanding a line, and IFS is defined as the...

Actually, this might work as well:
eval tgtfile=\""$(cat $srcfile)"\"

How about
while read line; do eval tgtfile=\""${tgtfile}"$line$'\n'\"; done < $srcfile

Well, I am afraid I really did not read you post well enough..

Try this instead, with the usual security caveats that come with the use of eval, especially in combination with environment...

You are using eval on the contents of an input which may not only creates a potential security risk, it also does not really make sense here since it interprets its arguments as shell commands and in...

$
$ cat dae2.txt
DELETE FROM CDH_STGN_${ENV1}.T1
;
INSERT INTO CDH_STGN_${ENV2}.T2
(
...
...

Hi R. Singh,
Note that you can easily put comments on multiple lines... You just have to put a # somewhere on each line before the continued comment text as in:
awk -v RP="$var" ' ...

Hello dae,

I thought you have to read variables from file, so I have given solution like that. Following explanation for sir Rudi's solution may help you in same.

awk -v RP="$var" ' ...

or even
awk -v RP="$var" '
BEGIN {for (n=split(RP, T, "[\n:]"); n>0; n-=2) REPL[T[n-1]] = T[n]
}
{for (r in REPL) sub (r, REPL[r])
}
1
' file

Hello dae,

Could you please try following and let me know if this helps.

awk 'FNR==NR{A[$1]=$2;next} {for(i in A){match($0,i);if(substr($0,RSTART,RLENGTH)){gsub(i,A[i],$0)}};print}' FS=":"...

You could also try one of these three portable ways to do it. (Note that the behavior of echo -e is not defined by the standards and varies from shell to shell and operating system to operating...