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With file1 .. file4 existing in PWD, I ran
for i in 1 2 3 4 5; do { sleep $i; ls file$i; } & done; jobs; for i in 1 2 3 4 5; do wait %$i; echo $?; done
[1] 7865
[2] 7866
[3] 7867
[4] 7869
[5]...

wait allows to specify a process ID or a job specification to wait for. man bash:

Similar, but with one essential difference.

Note that durden_tyler used double quotes around the variable expansion:
echo "$record"

Assuming "a k shell" = "Korn shell"


$
$ cat source_file
Daily|xyz|abc_def_tem_[0-9]\{8,\}|
$
$ cat process_file.sh
#!/usr/bin/ksh
while read -r record
do
echo "$record"
done <<<...

In addition to what RudiC and Scrutinizer have already said, why would you write a 28 line Korn shell function using a pipeline of echo and awk to get at awk's printf function when ksh's built-in...

To help you get on your way, try:
echo 'a|b|c|d|e|f' |awk 'BEGIN {FS = "|";column_length[0]=6;column_length[1]=3;column_length[2]=2;column_length[3]=3;column_length[4]=4;column_length[5]=5}...

You might want to try something like the following:
awk '
BEGIN { FS = OFS = "|"
}
FNR == NR {
hd[$0] = ++hc
next
}
FNR == 1 {
for(i = 1; i <= NF; i++)
if($i in hd)
of[hd[$i]] = i...

Where does your control file come into play? And, wouldn't you agree that it's way better to work on a short but meaningful sample?

---------- Post updated at 12:00 ---------- Previous update was...

Can I suggest redirect of stderr to stdout like this:

ls x 2>&1 | output_log

There are a number of ways to do this you could default to reading input if there are not parameters like this:

$ cat shell_script
#!/usr/bin/ksh

if [ $# -eq 0 ]
then
if [ -t 0 ]
then...

Understand that once expansion of the wildcard has happened it can't be taken back. The shell itself expands the wildcard before it passes what it has expanded the wildcard to to the respective...

abc\* or 'abc*'

Put your variables in double-quotes to suppress wildcard expansion and splitting.

echo "$1"