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If you want to disregard the first column, just print the sum:
print A[k]


By default, the order in which a for (i in array) loop scans an array is not defined; it is generally based upon the...

awk '
# Create an associative array: A for which value is sum of $2 and indexed by $1
{
A[$1] += $2
}

# End Block
END {
# For...

Depends how your files are structured, and how many of them are present. Try sth like (untested):awk '{RES[$1]+=$2} END {for (n in RES) print n, RES[n]}' file*

awk '{A[$1]+=$2}END{for(k in A) print k,A[k]}' file*

Which means that his sub($0,0) reads sub($0,0,$0)and should work fine. I'd rather guess it's to do with the E+which in regexes means "one or more occurrences of E", and the + is consumed, so it does...

Note that if all you want to do is replace every input line with a 0, there is no need for sub():
awk '{print 0}' infile > outfile
or
sed 's/.*/0/' infile > outfile
or
while read -r x...

The syntax of sub function is:
sub ( regex, replacement, target)
So it should be:
sub( /.*/, 0, $0 )
Also note that target is an optional argument. If target is not supplied it will use $0...

Perhaps you were looking for CONVFMT ?
awk '{for(i=1; i<=NF; i++) $i+=0}1' CONVFMT="%.10f" file

Output:
-6.8908090183 3.4934889171 1.4798836784 -2.2970763541 -3.4934236471 -4.4375847324...

X is nothing but an undefined variable. So substituting with X is same as substituting with null.

1 == true and 0 == false. When true, the default awk action is to print the record. So that 1 is...

Try awk '{for (i=1; i<=NF; i++) sub(/...........$/,"",$i)}1' fileI was trying to set and use the OFMT variable (as you obviously want to modify long mantissae), but this did not work in my linux/mawk...

awk '{for(i=1;i<=NF;i++) sub(/...........$/,X,$i)}1' file