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The double square brackets are important - the character class [:alpha:] replaces a-zA-Z, you still need the outer brackets to denote a bracket expression.
$ grep -Ewo "[[:alpha:]]" all.txt | sort |...

Of course. Change the last line of Yoda's script from:
' fileto:' file | sort -k8,8nr -k10,10nr

As I said before, add it to the last line of Yoda's script; so change the last line of his awk script from:
' fileto:
' file | sort -k10,10nr

Add to the end of the last line of Yoda's script:
| sort -k10,10nr
Let me know if you'd like to make the context or character value fields secondary or tertiary sort keys (ascending or descending).

Ok, I assumed you want to print previous record each time you encounter record: 200/202/203

Here is a modified awk code:
awk '
BEGIN {
A["200"]
A["202"]...

Based on some assumptions:
awk '
BEGIN {
A["200"]
A["202"]
A["203"]
}
$0 in A {
print "The context is "...

BEGIN and END are special patterns usually used for supplying startup and cleanup actions for awk programs.

BEGIN rule is executed once only, before the first input record is read.

END rule is...

You could use the awk END block to print the counter in the end:
awk -v S="$SEQ" '
$0 ~ S {
N++
}
END {
print N
}
'

Yes, this will not work for large files because your code is trying to load all records from your input file to an Indexed Array!

Instead you should follow the approach used in previous code. In...

I have previously posted similar codes which can be slightly modified to get your desired output.

So show us what you have tried so far, share your thoughts and efforts for approaching this...

I'm sorry. I misread your requirement. I thought you want to print records in the order that you have them in your input file.

If you have gawk then you can use below code to print in descending...

You can code something like:
SEQ=200
awk -v S="$SEQ" '
{
A[++c] = $1
}
END {
for ( i = 1; i <= c; i++ )
{
...

Yes you can. For implementing this change use regular expression comparison operators ~ and !~ instead:
SEQ="45654|234567|57899"

awk -v S="$SEQ" '
$0 ~ S {
V = $0
...

The first awk program that I posted loads all the records in your file into an Indexed Array A[++c] = $1 and in the end it performs the required operation.

This caused the program to throw Cannot...

How about this awk code?
SEQ=45654

awk -v S="$SEQ" '
$0 == S {
V = $0
getline
if ( $0 == 199 )
{
...

Khaled79,
Check this out:
# v=45654;perl -0777 -pe 's/$ENV{v}\n199\n225/$ENV{v}\n258/igs' file


235543
123
45654
258
578
45654
258

I didn't quite understand what you mean by variable sequence.

The program that I posted replaces 45654 199 225 to 45654 258

You just have to modify it as per your requirement.

Here is a solution using awk:
awk '
{
A[++c] = $1
}
END {
for ( i = 1; i <= c; i++ )
{
if (...