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This is a little bit simpler than SriniShoo's script and seems to do what was requested (but it doesn't print the trailing spaces that were included in the expected results shown in the 1st message...

awk 'NR == 1{p=$4; print $0; next} {$4 = ($4 == "") ? p : $4}1' file

I suspect this is not always correct.
I would prefer a simple
function min(a,b) {if (a<b) return a; return b}
and

Min[$8]=($8 in Min) ? min(Min[$8], min($9, $10)) : min($9, $10)

Dito with...

Try sth along this line (and expand):awk 'function min (M, V1, V2) {if ((!M) || V1<M) M=V1; if (V2<M) M=V2; return M}
function max (M, V1, V2) {if ((!M) || V1>M) M=V1; if (V2>M) M=V2;...

Put this into "script.awk":BEGIN {
a[9]=a[10]=a[12]=a[13]=a[15]=a[16]=a[18]=a[19]=1
}
NR==1 {
f=$1;n=$8;
for (i in a) {
m[i]=$i
M[i]=$i
}
}
{
for (i in a) {
...

Trying to remember analytical geometry ... quite some time ago ... awk ' {X[NR]=$1; Y[NR]=$2}
NR==1 {next}
...

Try

Let me know if it's helpful for you

$ cat file
10 464310.16
20 464309.44
30 464309.02
40 464316.93
$ cat int.sh
#!/bin/bash

awk '
{
x[FNR]=$1
y[FNR]=$2...

try

awk '{A[F]=$2>A[F]||!A[F]?$2:A[F]}
$1 == 1 && NR > 1{if(A[F]){print 1,A[F]};F++}END{print 1,A[F]}' file

If 2nd field is not sorted, using Jotne's idea:
awk 'NR > 1 && $1 == 1 { print $1, t; t = 0 } { t = t < $2 ? $2 : t }' file

Like this?
awk 'NR>1 && $1==1{print $1,t} {t=$2}'
1 4822
1 4882
1 4801
1 4801
1 4801
1 4801
1 4801
1 4801
1 4801
1 4801
1 4801
1 4801
1 4801
1 4801

awk '
$2 > max { max = $2 }
NR == 1 { next; }
$1 == 1 { print 1, max; max = $2; }
' filename
my code return one row less than your output! can it help you find your way ?

# cat file
A 0B 1828
C 100D 1666,C 200D 1727,C 300D 1783,
A 0B 1786
C 200D 1727,C 100D 1666,C 300D 1783,
C 400D 1812,C 600D 1869,C 500D 1841,
C 400D 1812,C 500D 1841,C 600D...

awk '/^[A-Z]/ {print $0} /^[0-9]/ { for (i=1;i<=NF;i=i+2) print $i,$(i+1) }' input.txt


Cheers,

awk '/HANDVEL/{print;next}{for (i=1;i<=NF;i=i+2) print $i,$(i+1)}' infile

Try

awk '$1=="CE2_12-15"{$2=(4086-$2)*2}
$1=="CE2_12-52"{$2=($2-836)*2}
$1=="CE2_12-54"{$2=($2-1088)*2}1' file

Hi

Altering the first part of the command:

$ awk '/=X/{if(x)print x;x="";}{if(x)x=x"#"$0;else x=$0;}END{print x}' file | awk '$0 !~ /^ROUTE/{print x, $0;next}{x=$0;}' | sort -t"(" -k2n,2 | \...

Hi


$ awk -F '[RG ]' '{print $2$3" = G,";}' file
103150111 = G,
103150121 = G,
103150131 = G,
103150141 = G,
103150151 = G,

Guru.

sed 's/[^0-9]*\([0-9]*\) \([0-9]*\)\(.\).*/\1\2 = \3,/' input.txt

How about:
awk 'p { print ($1+p)/2} p=$1' input.txt

Try this:

awk 'NR % 3 == 0' input-file >output-file


Should print as you want.

# awk '{a[x++]=$0;b[$1]++}
function calrnum(ar,i){
$R=ar[i];f=gensub(".*\\.","\\1","R")
if(f>=5){ar[i]+=1};if(i%2!=1){printf " %4d%s",ar[i],"B";}else{printf " %4d%s",ar[i],",A";}}
function...

Skrynesaver@busybox ~$ perl -Mstrict -e '
sub round{
my $num=shift;
return int($num + 0.5);
}
my $rec_id=undef;

while(<>){
my ($A,$B,$dat)=split(/\s+/,$_);
if($A != $rec_id){
...

Nice code guru.

But it needs a small correction

Hi


$ awk 'x!=$1{print "LINE ",$1,",";x=$1}{ print $2," = ",$2," ,";}' file1

Guru.

$ nawk -F\| '$1~/ 1 / && $4~/[0-9]/ && $2~/DISK/' *
$$ 1 | DISK | TR1311 | 1 |$$
$$ 1 | DISK | TR1312 | 1 |$$
$$ 1 | DISK | TR1317 | 1 |$$
$$ 1 | DISK | TR1313 | 1 |$$
$$ 1 | DISK | TR1319 | 1...