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There needs to be a ; or a <new line> char in front of the "then".

Assuming your test is how you want it, note the red semi-colon.
EDIT: Take note of disedorgue's comments for your test proceedure.
if [ $proc_out = "Normal completion" ]; then
echo 'match'...

Hi,
You must protect your variable with "...".
So, replace:
if [ $proc_out = "Normal completion" ]
by
if [ "$proc_out" = "Normal completion" ]

And add a newline in last line (you should check...