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Apologies for not noticing the updated question, I was answering your OP...

You still haven't told us what shell you use. It would be a lot easier to answer if you told us what shell you use. As...

try replacing ':' as as well as '/'

mydate_converted=`echo "$mydate" | sed 's#[/:]# #g'

Replace the slashes with spaces.


mydate="22/Oct/2011"
mydate_converted=`echo "$mydate" | sed 's/\// /g'`
mydate=`date -d "$mydate_converted" +%s`

Hi me_newbie,

A possible solution using 'perl':

$ cat infile
---some text---- 01/Jan/2010 ---- some other text ----
---some text---- 10/Jan/2010 ---- some other text ----
---some text----...

#!/usr/bin/ksh
typeset -i mI
set -A mMon n/a Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
mFrom='20100105'
mTo='20110101'
while read mLine; do
echo ${mLine} | sed...

tail -1 filename

sed -n '$p' myFile

Try: awk 'END{print $0}' file

Yes,

-t/ - fields are delimited by forward slash(es) `/'

then in order:

-k3n - sort numerically by the third field
-k2,2M - sort by month considering only the second field
(not from the...

sort -t/ -k3n -k2,2M -k1n infile

There is indeed:

awk 'BEGIN {
# Set up arrays for name-to-monthnumber
split("Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec", MON, "|");
for(N=1; N<=12; N++)...

we must firstly use the sort command, because of uniq command process for sequential lines.therefore we use firstly sort command for get the sequential lines.
# cat file
a b
b c
a b
d c
a b
a...

how about your input file?
maybe you can try like this.(while FS is space!)
$ cut -d" " -f1 file_name|sort|uniq -c|sed 's/ *\(.*\) \(.*\)/\2 \1/'

regards
ygemici

That's just a simplified version of what you already did...

awk '{ C[$1]++; }
END { for(K in C) print K, C[K]; }'

Please don't bump.

-F tells awk what to use as a separator -- where fields stop and start. It's a regular expression. Any single , . ? \ ! will stop the current record and start the next.

...

it works fine... thanks everyone

hats off to itkamaraj