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Very good, congrats!
You may want to have string fields left justified; then, use a minus sign: "%-4s".

That's because awk treats any number of spaces as field separator (unless told otherwise). As you can see, the formatting has already gone in the first action's output. If you need exactly formatted...

Try logging in to a pseudo terminal, or via ssh to the VM, then post the output of ls -l /home and df -h

awk '{if (j==0){j++;print;next}
for (i=1;i<=NF;i++) {
sum+=$i;
}
j++;
if (j == 21){$21=sum;j=0;sum=0}
print $0}' MatrixFile

I noticed some inconsistencies in your requirement!

If you want to split each alpha-numeric string greater than 3 character length, then why the following highlighted 4 character length string is...

Try something like this:
awk '/^HUMAN/{print > ( "set_" $3 )}' file

Hey, come on, be reasonable, and be creative. If you want to print "with", embed "with" into the text.
And, for "last underscore", man bash:

Try also:$ echo filename is ${f%_*} serial no. ${f#*_} | cat - $f

#! /bin/bash

f="asdf_432"
x=${f%_*}
y=${f#*_}

sed -i.bak "1i filename is $x serial no. $y" $f

Try this,

echo "assa dsad werr vdss a.txt is 2.4
assa dsad werr vdss b.txt is 3.2
assa dsad werr vdss c.txt is 4.3" | eval mv `awk '{f=$5; sub(/.txt/,"",$5); print f" "$5"_"$7; }'`

This...

The solution in post #2 works for me on my GNU/Linux running bash 4.1.10.
Could you please post the output of uname -a and bash --version

#! /bin/bash
while read v1 v2 v3 v4 v5 v6 v7
do
[ -e $v5 ] && mv "$v5" "${v5%.txt}_$v7"
done < filenamelist.txt

nawk 'FNR==NR {f1[$2]=$0;next}{print ($1 in f1)?f1[$1]:"ABSENT"}' firstFile secondFile

awk 'NR==FNR{a[$2]=$0;next}{print a[$1]?a[$1]:"ABSENT"}' file1 file2
1 a rew sdf ghd 234 gfd 345
ABSENT
7 c dns esd lkn 765 nkc 093
4 d bhj asd klj 231 kljn 211
ABSENT
3 f hjk kln ghj 879 nkj...

Well, use shell or awk, not both.

sed '
/^[0-9]* PRO /!d
s/.* //
' your_file |sort -nu | read key5

grep "^[0-9]* PRO .* $key5$" your_file


The file name of a list of file names...

Try: awk '!a[$2]{a[$2]=$0;m[$2]=$5}$5<m[$2]{a[$2]=$0;m[$2]=$5}END{for (i in a) print a[i]}' file

I think I get it...

awk -v DATA1="datafile1" 'BEGIN {
COMPLETE=1
# Read lines like 'fds 21 sdf 32 6432', so A["21"]="6432" etc.
while(getline <DATA1)
{
...

Try:awk 'NR==FNR{a[$1]=$5;next}{print a[$0]?a[$0]:"ABSENT"}' file1 file2

Try: awk '{if(m[$1]>$5||a[$1]==""){a[$1]=$0;m[$1]=$5}}END{for (i in a){print a[i]}}' file
PS. for your sample data, correct output seems to be:9 ALA 9 ALA 0.00000
16 ALA 16 ALA 0.000000

No need for 'paste'; that tool is used to merge lines. I assume the file liist has the filenames to be processed, one per line, right?
The redirection operator you have there, '>' will truncate the...

Put your strings ALA, ASD, etc all in one file, one per line. Let's call this file 'strings'.
Then you can do:

while read aa ; do
awk '$2=="'$aa'" && !($1==$3 && $5==0){print}' input | sort...

hmm lets try this:)
paste list1 list2|while read f1 f2 ; do
for string in ALA VAL #-> (20 strings will be here)
do awk 'NR==1{s=$20;next}$5==s&&$2=="'$string'"{a[i++]=$4};...

Hi,you can try this..
paste list1 list2 | while read f1 f2;do
awk 'NR==FNR{a[$20]=$20;b=$4;next}a[$5]{print b"\t"$4}' $f1 $f2;done


regards
ygemici

ummm... sorry I forgot a redirection operator:
while read f1 f2 ; do
awk 'NR==1{s=$1; next} $2=="ALA" && $5==s {print $4} ' $f1 $f2
done < <(paste list1 List2)

or, in a more concise way:...