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SS_[0-9]*_[0-9]*.zip

How about ls SS_[0-9]*.zip You may need to refine the pattern.

Try: awk -F\; '{x=$1 FS $2 FS $3;for (i=4;i<=NF;i++){print x FS $i}}' input_file

nawk -F';' '{head=($1 OFS $2 OFS $3); for(i=4;i<=NF;i++) print head,$i}' OFS=';' myFile

file1=somefile.txt
file2=anotherfile.txt
resultfile=somefile_minus_anotherfile.txt

awk -v file1="$file1" -v file2="$file2"
FILENAME==file1 { arr[$0]++}
FILENAME==file2 { if...

sed -i '1i add here' file*bat

awk '
FILENAME=="file1" { arr[$0]++}
FILENAME=="file2" { if (arr[$0]==0) {print $0} }
' file1 file2 > file2minusfile1.txt

will give file2 minus file1, i.e., data in file2 that...

You can try as,

00 23 * * * [[ $(date +'%d') -eq $(cal | awk '!/^$/{ print $NF }' | tail -1) ]] && job 1>/dev/null 2>&1

hth.

Code tags please, thanks.

to be ran at 11pm on the last day of a month:

00 23 * * *[ `date +%d` -eq `echo \`cal\` | awk '{print $NF}'` ] && myJob.sh