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There is also the base64 program that's part of the GNU coreutils:

$ base64 --help |grep -F -- -d
-d, --decode Decode data.

echo "YOURSTRING" | perl -pe 'use MIME::Base64; print MIME::Base64::decode($_);'

https://www.unix.com/shell-programming-scripting/17620-decode-email.html

echo 'chris martin 200173 845747 mech engineerchris' |
sed -r 's/([^0-9]*)([0-9 ]*)([^0-9]*)/var1=\1\nvar2=\2\nvar3=\3/'

GNU sed. Change "(" and ")" to "\(" and "\)" for another one (and remove...

Then try to pattern match it with command sed. You cannot pattern match as highlighted above.
Still not very clear with your requirement. Please brief again and post the exact contents of variable...

Assuming "abc" is your pattern: perl -nle 'print "$1 $2" if /(\d+) abc (\d+)/' file

echo "1234567890 abc 1234" | awk -F "[a-zA-Z]*" '{print $1 $2}'

if u have the character in a file then
awk -F "[a-zA-Z]*" '{print $1 $2}' sample.txt
where $1 will be before the pattern and $2...

So you just want to remove digits from the input file? If so, try this: sed 's/[0-9]//g' infile > outfile

you may try something like this
echo "aB12Cd" | tr -dc '[a-zA-Z]'

so you need to check for var1 in var2 with any number of spaces randomly inserted?

var1="abc"
var2="a b c def"
pattern=$(echo $var1 |sed 's/\(.\)/\1 */g')
echo $var2|sed "s/^$pattern//"

...

Here VAR3 holds the "remaining stuffs" from VAR1 if it matches VAR2.
VAR1="AB CDEF"
VAR2="ABC"
VAR3=$(echo "$VAR1" | sed -n "s/ //g; s/$VAR2//p")

Is this what you want:
echo 'ab cdef' | sed 's/ab[ ]*c//'

could you show us what you actually tried and explain what you are hoping to find in the file...

Try this:

line='nramak|BFS|121 * 789 * 85#2[123]|7539|'

param4=$(
printf '%s\n' "$line" |
cut -d\| -f3 |
tr ']#[' ' '
)

printf '%s\n' "$param4"

We'll need to see a sample of your input and an example of the desired/expected output.

It's not awk, it's the shell ...
You need to quote the parameters in order to avoid shell filed splitting and filename generation (globbing)!

PARAM4=`echo "$LINE" | nawk -F"|" '{print $4}'
echo...

$ echo $test
a b c d e f g

$ echo $search_string
abc

$ echo $search_string | while read -n1 char; do test=`echo $test | sed "s/$char//"`; echo $test; done
b c d e f g
c d e f g
d e f g

Try..
echo 'this too [will [pas]s b[y]' | sed 's/[][]//g'

echo '-asadjh--nfkdjnf------nfjksnfjkd'|tr -s '-' ' '

Try:sed 's/-+/ /g' file

Try with below

i=0;
if [ $i -eq 0 ]; then
echo inside if
fi


In case you want to debug your script put below code at the very beginning


set -x


Cheers
Harish

"tr" can be used instead of "sed" and would likely be faster:
echo '/ and \' | tr -d '\\/'

echo '/ and \' | sed 's/[/|\]//g'

$ echo "\/" | sed -e 's,\/,,' -e 's,\\,,'

$ echo "\/"
\/
$

echo '85743975945738' | awk '{print substr($0,0,4)"-"substr($0,5,4)"-"substr($0,9)}'