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Hello nikhil jain,

Could you please try following.


awk 'BEGIN{FS=OFS=",";s1="##"} FNR==NR{a[$2,$3,$4]=a[$2,$3,$4]?a[$2,$3,$4] FS $1:$1;next} (($2,$3,$4) in a){print a[$2,$3,$4] s1...

Hi, try something like this:

awk -F, '
{
i=$2 FS $3 FS $4
A[i]=(i in A?A[i] FS:"") $1
}
END {
for(i in A)
print A[i] "##" i
}
' file

Don't use uuencode, here is an example (https://www.unix.com/302940250-post2.html) using base64 and sendmail

No idea by yourself on how to go about it?

Building on what Don Cragun posted, try
awk -F, '
BEGIN {m = 9
}
$9 ~ /^(High|Critical)$/ &&
$7 == "availability" {c[$6]++
...

Maybe you want something more like:
awk -F, '
BEGIN { m = 9
}
$9 ~ /^(High|Critical)$/ && $7 == "availability" {
c[$6]++
n[$6] += $11 == "NO"
y[$6] += $11 == "YES"
if(length($6) > m) m =...

I'm glad I could (almost) help. For your required modifications, why don't you give it a try, with 168 posts and a six year membership?

Hello nikhil jain,

If you want duplicates into your answer then following may help you in same.

awk '/Student/{A=$0;next} /bytes/ && A && $2 > 1000{print A;A=""}' Input_file
If you don't...

If the patterns are always fixed strings the usage of fgrep or grep -F may result in a HUGE Performance Boost.

If possible, run fgrep without -i. That'll get you another Performance Boost and also...

Hello Nikhil,

There seems to be space at last of your lines, so could you please try following and let us know if this helps.

awk -F"|" 'NR==1{print $2 FS $3 FS "CNT";...

You didn't answer my question, so I go on with my idea. Try

awk 'NR==1 {print $2, $3, "CNT"; next} {SUM[$2 FS $3]++} END {for (s in SUM) print s, SUM[s]}' FS="|" OFS="|" file
Col2|Col3|CNT
POSIX...

Here is a commented version of the script I suggested:
#!/bin/ksh
# Set IAm to the final component of the pathname used to invoke this script.
IAm=${0##*/}

# If the number of operands given to...

Hello Nikhil,

In case you need only those lines which are having more number of delimiters following may help you. Taken code from RudiC's suggestion with a minor edit in it as follows.

awk -F...

Try awk -F '|' 'NR==1 {n=NF} NF-gsub(/\\\|/, "&")!=n' file
1|Raj|null|

Try:
awk -F '|' 'NR==1{n=NF}NF>n' file
or if it is either less or more:
awk -F '|' 'NR==1{n=NF}NF!=n' file

not sure. try:
awk '
NR==1 {for (cc=1; cc<=NF; cc++) n[$cc]=$cc; t=$0; next;}
{
if ($1 != "0") c[1]++;
for (i=2; i<=NF; i++) if ($i != "NA" && $i != "null" ) c[i]++;
}
END {
print...

Try this awk solution:awk -F, '{for (i=1; i<=NF; i++) if ($i~/^"build":/) $i="\"build\":\"" PARM "\""}1' PARM="abcd release" OFS="," file
,"environment":"accent-release","build":"abcd...

Removed first forward slash
sed 's/"build":"[^"]*"/"build":"sdk-1971_00_label_npr-release_releasevalue-1971_00_label_npr-release_releasevalue"/g' File

Is your requirement really to find all files called v.info below /o but only once per immediate subdirectory? You could mangle that with something like:-cd /o
for subdir in *
do
find $subdir...

I can't really test this, but I think it will work, if I understand the question:

pnos_save_file=$HOME/pnos_save_file.txt
num=1
dat10=`date "+%m/%d/%Y" -d "+10 days"`
dat=`date "+%m/%d/%Y"`...

I tried

echo "1.04/1.05ELA=20000,POLLK=35000,RH=5000,MH=7000,WH=4359
1.7:ELA=2000,POLLK=2000,RH=2000,MH=2000,WH=607
1.9:ELA=2000,POLLK=2000,RH=2000,MH=2000,WH=396...

I'd bet your file has windows control chars in it, at least a <CR> at the end. Get rid of those and it will fly.
And, in the regex, you don't need the \ in front of the $ sign representing the line...

Try:
awk -F'[ \t]+,[^,]+,' '$1=$1' OFS=, fileawk '{gsub(/[ \t]+,[^,]+,/,",")}1' fileperl -pe 's/\s+,.*?,/,/g' file

awk -F, '{ s=$1;for(i=2;i<=NF;i+=2) s=($i~/^[ ]*$/)?s FS 0:s FS $i; print s }' filename

Your last requirement "undefined lines should have 0 value" applies for a matrix (two dimensional array).
Which GNU/Posix awk:
awk -F, '
FNR==1 { ++xm }
FNR>ym { ym=FNR }
{ a[FNR,xm]=$2 }
END {...

Built on Jotne's proposal, you may want to try:
$ awk -F, '{C5+=$5; C6+=$6; C7+=$7; C8+=$8; R=$5+$6+$7+$8; $1=$1; print $0, R}
END {print "total",x,x,x,C5, C6, C7, C8, C5+C6+C7+C8}
...