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Pipe it?

find . -path './*' -prune -type f -name '*20161212*' ! -name '*.out' -exec strings {} + | grep something

Please, test the following:

find . -path './*' -prune -type f -name '*20161212*' ! -name '*.out' -exec strings {} +

Sorry I misinterpreted your requirements and believed you had a number of values in the range of 00 thru 99 and not all the values.

to match any two digit number I would use:

strings *.* | grep...

'ABC.{134}10'
ABC = 3
.{134} = 134
10 = 2
The 1 from the number 10 is found WITHIN a string of 138 matched elements and the 0 from 10 will be WITHIN a string of 139 matches.
There is no anchor...

You could try this:

strings *.* | grep "ABCD" | cut -c 521-522 | egrep '(10|11|20)' | sort | uniq

If your list of values is quite long you could put them in a file with 1 line per value and use...

With awk:
awk -F "|" '
# hash the search list
NR==FNR {L[$1]=0; next}
# now procede with the data files
# print if the following is true
($4~/^3078=/ && ($2 in L) && L[$2]++==0)
'...

Sorry clippertm,
I think the problem of output all occurences is that we used the wildcard *.*
so maybe we must use sort after grep
Or use perl or awk as apmcd47 say, u know, both...

Your first problem is that you need to match the patterns in your pattern file with the second field. You cannot just use grep -f list.txt. You really need to use awk or perl. You can then...

Sorry clippertm,
I made a mistake, delete the double plus.
grep -h '4=[745-755]' *.* | grep '3078=' | sort -u -t'|' -k2,2?
If [745-755] is not available, use this:
grep -h...

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