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Just for your information, this can also be done using the dos2unix command

vi test.txt

:%s/.*/&@test.com/when in vi in command mode, use
:set listto enable the display of invisible caracter
:set nolistto disable the display of invisible caracter

@spirm8, your sed statement is correct and it should not be doing that. There probably is something wrong with the input file. What platform are you on, how did you create the input file.
Also,...

# for i in `sed "" file2`; do sed "/$i/d" file1 1>testf && mv -f testf file1; done ; more file1
4
5
6


# comm -3 file2 file1
4
5
6

# diff file2 file1 | sed...

Strange. With your input I get:
4
5
6

--

With the samples you provided, this should work too:
grep -vf file2 file1

IMO franklin's suggestion just needs a print $2 action. Plus I would tend to use $1 instead of $0 in the first part to avoid possible mismatches due to spurious spacing...
awk 'NR==FNR{a[$1];...

If your grep version supports the -f option:
grep -f file1 file2

Otherwise with awk:
nawk 'NR==FNR{a[$0]; next}$1 in a' file1 file2