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if [ "$USER" = "admin1" ] || [ "$USER" = "admin2" ]
then
echo "Run scripts here"
else
echo "Run script as admin "
exit 1
fi

Your test can't be but true, use an AND, not an OR:

if [[ $USER != "admin1" && $USER != "admin2" ]]; then
...

USAGEPERCENT=$( awk "BEGIN{print ${ARR[21]} / ${ARR[19]}}" )
USAGEPERCENTTOTAL=$( awk -v p="{USAGEPERCENT}" 'BEGIN{print int (p * 100)}' )

Hi Jimbob,

As I said I'm a bit restricted as to what I can do with awk, but it may be the variable itself - I'm not sure if it should be prefixed with the $ and enclosed in {} - you could try it...

I'll break it down, then.

Just initialization
N=0
ARR=()
# Special variable which controls when unquoted variables split.
# By default it's space, but we want to split on , for the csv...

You need the {} brackets.

echo ${ARR[2]}

---------- Post updated at 04:45 PM ---------- Previous update was at 04:42 PM ----------

I think I made an error in my original code.

set -- $STR...

#!/bin/bash

N=0
ARR=()

IFS=","

while read STR
do
set -- "$STR"

while [ "$#" -gt 0 ]
do
ARR[$N]="$1"
((N++))
...

First off, awk doesn't know that it's supposed to split on commas unless you tell it. It won't know to print out commas unless you tell it, either.

# -F controls the input separator. You want ,...

Try: awk -F, -vOFS="," '{print $3,$8}' myfile.csv > mynewfile.csv

man grep

simple example

grep foo bar.txt | less