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sh two.sh "$param1" "$param2"

change one.sh


echo "JOB STARTED"
echo "JOB START TIME: `date +%D:%H:%M:%S`"
echo "give parameters:\n param1:"
read param1
echo "param2:"
read param2
sh two.sh $param1 $param2
echo "JOB...

Do you mean the last line has no trailing newline? In that case you may or may not be able to use sed some can, but some cannot handle that. Try printf "\n" >> file

--
@hanson44: most seds cannot...

I think this will add newline to end of last line:
sed "$ s/$/\n/" infile > outfile

You need to use files that are in unix-format, not DOS-format. To convert:
tr -d '\r' < infile > outfile

This is another way of doing it with awk which works for me:
awk 'BEGIN{while((getline f<FILENAME)>0){if(length(f)>l)l=length(f)}}{printf "%-"l"s\n",$0}' file

awk 'NR==FNR{if(length($0) > maxlen){maxlen=length($0)}next}
{printf "|%-"maxlen"s|\n",$0}' file1.txt file1.txt Once you are confirm with o/p then remove "|" from the above code

Rather try awk -v l="$LEN" '{s="%-"l"s\n";printf(s,$0);}' $FILE > temp1.txt;orawk -v l="$2" '{s="%-"l"s\n";printf(s,$0);}' $1 > temp1.txt;

FILE="partial.txt"
LEN=285

echo | awk -v l="$LEN" -v file="$FILE" '{s="%-"l"s\n"; while(( getline line < file ) > 0 ) { print s,line; } } '