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OP wanted everyline to be printed right?

awk 'BEGIN{FS="*"; OFS="*"} /^ABC/{$7="13"}1' input_file


BTW, 1 here is WHENTOPRINT which is true and prints everything by default.

--ahamed

That looks like a fine illustration of awk's basic principles actually :) I'll just comment it a bit more:

# awk code blocks work like CONDITION { code } WHENTOPRINT
# For each line, { code }...

awk -F\| '{print > $1"_xyz.dat"}' inputfile

Hi, try this:
awk -F\| '{n=$1"_xyz.dat"}f!=n{close(f);f=n}{print>f}' file

There's no need to resubmit your post. But you also don't need so many, especially bright, colours - red-blue-red-blue-red would work for me!

Now, if you had used code tags...

Hi, see if this works:
sed '$d;s/.......\(....\).\(..\)\(...\)...\(...\)....\(...\).*/\1|\2|\3||x|\4|0\n\1|\2|\3||y|0|\5/' infile2345|98|809||x|969|0
2345|98|809||y|0|537
2345|97|809||x|544|0...

awk 'BEGIN{FS=OFS="|"}{y=$6!=x?0:y;x=$6}$5=++y' file

awk -F\| '$5=NR' OFS=\| file

Try: awk -F\| -vOFS=\| '{$5=NR}1' file