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Hello,

Could you please try the following code, hope this helps in variable named s1 you can set the date value which you want to get in output.


awk -F"=" -vs1="20140827" '/^\$\$TODAY/...

[user@host ~]$ x=20140819; sed "s/=[0-9]\{8\}/=$x/" file
SomeTextGoesHere
[ASD.EXAMPLE@ABCD]
$$TODAY_DT=20140819

[FGH.EXAMPLE@ABCD]
$$TODAY_DT=20140819

[QWE.EXAMPLE@ABCD]...

Try:
for i in *.dat_*
do mv "$i" "${i%.dat_*}.dat"
done

try this:
#!/bin/bash

ls *.dat_* | while read line
do
part1=$(echo "$line" | cut -d"." -f1)
mv "$line" "$part1.dat"
done


edit / another approach:
rename 's/\.dat_.*/\.dat/' *.dat_*