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Match lines with description and only replace data values in 2nd item (This is closer to OPs original script):

awk -F\" 'NR==FNR&&/description/{a[$2]=$4;next}/description/{$4=a[$2]}NR!=FNR'...

try: awk 'NR==FNR{a[$2]=$3;next}{$3=a[$2];print $0}' source tobe

awk '$NF="|"$NF' infile

Try this,

awk -F"|" 'BEGIN{a["JAN"]="01"
a["FEB"]="02"
a["MAR"]="03"
a["APR"]="04"
a["MAY"]="05"
a["JUN"]="06"
a["JUL"]="07"
a["AUG"]="08"
a["SEP"]="09"
a["OCT"]="10"
a["NOV"]="11"...

sed '/^$/d' infile will delete empty lines, but not whitespace-only lines..

sed 's/=[^,]*/=0/g' infile

GNU sed:
sed 's/ /|/g;s/|/ /12g' infile

awk 'NR==FNR{a[$1];next} {for (i in a) {if ($0~i) sub(i,i "_EDITED")}}1' Read.txt input.txt

Or:
b=_EDITED

while read i
do
sed "s!$i!$i$b!" input.txt > temp
mv temp input.txt
done < read.txt

If your sed version supports the -i option:
b=_EDITED

while read i
do
sed -i...

try this,


#!/bin/sh

cp input.txt temp_forum.txt
a=`cat read.txt`

for i in $a
do
if [ -f temp1_forum.txt ]
then
cp temp1_forum.txt temp_forum.txt
fi
b=_EDITED
c=$(echo $i | sed...

It is not working as you expected, because regexp can also match from middle of the line to the end. So it matches like this:11111112
111111112
To match only from the beggining of the line use:grep...

Hi.

Your description could be considered slightly ambiguous, but:


$ egrep '^-[0-9][a-z]+[0-9]-$' file1
-1xyz1-
-2ab1-

awk -F\" -v dir="dir1/kernel" '$2~dir{print $4}' file
If is not what you want , please post a sample of your List file, xml file and desired output base on example.

I believe .svn are hidden directories used by subversion, not files. If so, rm without -rf won't remove them. Also, if they are directories, since they're going to be nuked, it's best to exclude...

Something like this ?


$
$
$ # show the entire file hierarchy from the root directory "Project_Src"
$ find ./Project_Src -name "*"
./Project_Src
./Project_Src/x1.svn
./Project_Src/Dir_B...