Search Results

Yes, modify the printf statement, put format specifier:
printf "%s", OFS A[i];

Here is the modified code:
sort file | awk -F'|' '
(P[1] == $1) && (P[2] == $2) {
n = split ($0, A, /[|]/)
printf OFS
for ( i = 3; i <= n; i++)
printf...

sort file | awk -F'|' '
A[1] == $1 && A[2] == $2 {
n = split ($0, A, /[|]/)
printf OFS
for ( i = 3; i <= n; i++)
printf OFS A[i];
printf RS
}...

just change

output=$(grep "ERROR" $logfile|grep -v "pattern that u don't want to match")

man grep:

-v, --invert-match
Invert the sense of matching, to select non-matching...

Does this give you what you want (from your original file)? If it does, format the output as per your requirement.
gawk -F: '{for(i=1;i<NF;i++)
{
n=split($i,e,/[-;|]/)
exists[e[1]]
...