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Unix sed needs
sed 's#\.\.\(/\.\.\)\{0,1\}#%HOME%#' file

Well, try


sed -r 's#\.\.(/\.\.)*#%HOME%#' file


-Ranga

You use the N to append the next line and loop back if COMPANY is not there:sed '
:lopp
/COMPANY/!{
N
b loop
}
.
.
.
'
The resulting buffer matches...

Yoda, your answer is not correct; it'll match !/^Date/ in the entire file!
It is necessary to have a kind of state; awk and a state variable is appropriate.
awk '/^Date/ {s=0}...

Try this

sed -e '/\['$section'\]/ {
:skip
n
/^$/!b skip
i\
'"$line"'
}' wav.test

That is OK, "SunOS 5.10" already puts it in perspective. Note that with SunOS you need to use the tools in "/usr/xpg4/bin/" rather than in "/usr/bin". What is your "PATH" variable looking like?

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