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Have you tried not escaping at all?sed 's/$(variable #)/HERE/' input

That was just an example. Use bash instead, replace print with printf:
#!/bin/bash

while :
do
printf "%s" "A1: "
read A1
[ ${#A1} -le 8 ] && break
done

This should easily let you input an exact string to take as the string to reject.

$ cat regafter2.awk

# Recall N lines ago up to 9 lines
function last(N)
{
if(N>L) return("");
...

sed -n '/Example Hello/,/Example/s/Text.*/&/p' myFile

Something like this?awk '/<Name>/{$1=$1;n=$0}/<EditField>/{$1=$1;e=$0}/<Title>/{$1=$1;t=$0}/<\/Column>/{print e?n","t","e:n","t;e=""}' file

Try: awk '/<Name>/{$1=$1;n=$0}/<EditField>/{$1=$1;e=$0}/<\/Column>/{print e?n","e:n;e=""}' file

---------- Post updated at 09:22 AM ---------- Previous update was at 09:20 AM ----------


This...

| cut -b-9
No need for delimiters if Youre writing bytes (chars).

Because your quotes are in the wrong place. Try this:



var="`echo test.txt | cut -d . -f1`"


Or the preferred way (no backticks)

var=$(echo test.txt |cut -d . -f 1)

You're on the right track. The redirection to $word.txt needs to happen inside of the loop. Yes, you can redirect the output of the loop to a file, but that output file is opened once by the shell...

Assuming that XXXXKV is always preceded with a space this should work:


sed 's/ [^ ]*KV.*//' input-file >output-file


From your original post you want the 230 from 230KV to be removed too. If...

didn't read carefully, sorry ;)

you have a wrapped line AND you don't need '#!/bin/bash':

BEGIN {
dirN=split("right left", dirA, FS)
}
/margin-/ {
for(i=1;i<=dirN;i++)
if (match($0,"margin-" dirA[i]...

have you tried the code I've posted?

sed 's/.*ID="\([^"]*\)".*NAME="\([^"]*\)".*AGE="\([^"]*\)".*/\1 \2 \3/' infile |grep -v "<\/Identifier>"

This code actually stores the source text of a webpage and will work pretty nice in this case:
#!/usr/local/bin/python

import urllib
import os

# get data
f =...