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awk '$6==55{sub("^01 ","07 "); sub("^02 ","17 "); sub(/^3[16] /,"67 ")}1' infile




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That is equivalent to
awk '$1 ~ /[01236|]/ && [..]
This may be what you were after:
awk '$1 ~...

Or if you like long one-liners ;-), this works:


awk '$1 ~ /[01|02|31|36]/ && $6 ~ /55/{sub("01","07");sub("02","17");sub("31","67");sub("36","67");print}' file

07 AAAAAAAA AA AA 1111 ...

You can do something like this:
BEGIN{}
{
if ($1 == "01" && $6 == "55"){
s = $0
sub("^01","07",s);{print s}
}
else if ($1 == "02" && $6 == "55"){
s = $0
...