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Try:
for (( j=$k; j<=$m; j++ )); do

Simply negate the tests so you will print the data line if it is not a part
of the "set" array, and print all lines that don't start with "|" as below,
assuming you want to see all the headers and...

You can use sort and comm to find lines in one file's set or another or both, dividing your set.

Using Perl -


$
$
$ cat f8
DONOR ACCEPTORH ACCEPTOR
atom# res@atom atom# res@atom atom# res@atom %occupied distance angle
| 4726 59@O12 | 1487 19@H12 1486 19@O12 | 85.66 2.819 ( 0.18) 21.85...

Seems to me that you could use modulus to simplify the tests.

Your number x (assumed to be less than or equal to 64?)

if x % 8 = 0 it's in the right hand column
if x % 8 = 1 it's in the...

I'v never programmed in Fortran. So consider this as pseudocode:


perl -e'
$n = 100;
$k = 2000;
$i = 0;
$j = 0;
$step = 1;
while ($i < $n) {
$j = 1;
while ($j <= $k - $step) {
...

thru sed..
sed '1000~1000!d' inputfile > outfile # every 1000th line starting from line 1000
sed '1~1000!d' inputfile > outfile # every 1000th line starting from line 1

awk '!(NR%1000)' file

Try:
awk '!(NR%1000)' infile