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In addition, I would consider using $2!=pid, since at some point, the numbering of processes may start anew, so an earlier process is not always guaranteed to have a lower number..

$$ is special variable of the shell (not of awk). Shell's variable are not visible inside awk (the way you have used in your code).

You may want to consider

awk -v pid=$$ '{if ($2<pid) print...