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Try:
awk 'NR==3{sub($1,sprintf("%.9f",$1*0.96))}1' file1.txt > file1_new.txt

Try awk 'NR==3 {$1*=0.96} 1' CONVFMT="%.9f" OFS=" " file
2.259314750 xxxxxx
1.962774350 xxxxxx
2.800144598 xxxxxx
1.355026900 xxxxxx
1.677389740 xxxxxx...

Try sed with “i” command to insert a line before match for your request to add only one line.

$ cat file.txt
1
2
3
4
5
$ sed "4 i\Inserted new line" file.txt
1
2
3
Inserted new line
4...

Insert line after every 7th line:
sed -n 'p;n;p;n;p;n;p;n;p;n;p;n;p;i\inserted line' file_1 >file_2

Hello,

Here is an awk example for same, it may help.
For example an input file is:


1 5
2 4
3 3


Code is:

awk 'NR==2 {print "checking the insertion."} 1' file_name


Output...

Try:
awk '!((NR-1)%m),!((NR-p)%m)' m=291 p=288 file

I think you can use the head and tail commands to achieve what you want.

If the line numbers, filenames, and string to be replaced are all the same, the directories are literally named "dir<digit>", and the replacement string is the same <digit> as found in the directory...