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You could check the value of $n like this (i guess you forgot what is in red below) :

n=$(sort /Users/Natalie/1/kuku.txt | tail -1)
echo $n
exitWhen you make sure the value is correct you can...

Here is a simple starter solution...
#!/bin/bash --posix
# num.sh
data="2013102100"
data1="${data:0:4}"
data2="${data:4:2}"
data3="${data:6:2}"
data4="${data:8:2}"
echo "$data1 $data2 $data3...

In the future, to not waste anyone's time, please mention in your problem statement that you are not interested in AWK solutions (or that you require a sh-only solution). This same issue occurred in...

Sorry I was not knowing :)

While there may be combinations of AWK implementation and operating system on which your suggestion is faster, I compared it against its predecessor on two combinations and yours was slower...

This was very interesting, and an eye opener. I have never tested this, just thought i many be solver to run ting in loop. This prove it many be wrong.
Thanks for taking time to test. :)

See my post in this forum https://www.unix.com/shell-programming-scripting/237555-finding-average.html
At the end it divides the sum to find the average.

Longhand on OSX 10.7.5 default bash terminal:-
Last login: Thu Oct 10 07:41:49 on ttys000
AMIGA:barrywalker~> data=2013101173
AMIGA:barrywalker~> data1=${data:0:4}
AMIGA:barrywalker~> echo...

I try to avoid loops in awk to speed things up. If you have gnu awk, you can do this:
awk '{a+=$1} END {print a}' RS=" |\n" file?
1779
If you like to store this into a variable do this:...

script.ksh
for num in `cat $*`;do((t+=num));done;echo $t
... or ...
awk '{for(i=1;i<=NF;i++)t+=$i} END {print t}' $*

echo 5 6 | sh script.ksh