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If you want to verify before running the code, comment the mv part and include echo "{j}"
for i in *.pdf
do
FNAME=${i%.*}
EXTN=${i##*.}
BNAME=$(tr -dc '[:alnum:]' <<<${FNAME})
...

Hello Ambijat,

Please find attached the example for removing the punctuations in lines.


echo "A~\`\!@BCDEFGH" | sed 's/[[:punct:]]//g'


Output will be as follows. You can take...

Hi, those are parameter expansions (https://www.gnu.org/software/bash/manual/html_node/Shell-Parameter-Expansion.html).

You do not need arrays, nor do you need external programs. You could also try:
#!/bin/bash
for file in *.pdf
do
tofile=${file//[[:punct:]]/_}
tofile=${tofile%_pdf}.pdf
mv "$file"...

Hello ambijat,

Untested but you can try awk also for same.


echo ${a[i]} | awk '{gsub(/[[:punct:]]/,X,$0); gsub("pdf",".pdf",$0);print $0}'



Thanks,
R. Singh

Note that the original request was to delete punctuation characters except for a chosen list of punctuation characters to be exempted. This script will also remove whitespace and control characters....

You can just use the [:space:] character class like :

sed 's/[^'$a'[:space:][:alnum:]]*//g' myfileOr if you want keep the space and remove they other type of space you can just :

sed 's/[^'$a'...

Yup, should be possible, just a little example :

# cat myfile
Bb2$£¤µ%§\°~`!@#$%^&*()_-+={[}]|:;"'<,>.?/
# a="@#+="
# sed 's/[^'$a'[:alnum:]]*//g' myfile
Bb2µ@#+=
#

# a="#@|_%"
# sed...

Why not to use alnum instead of punct ?
Just add in the list the character or class you want to keep (like @ and # ) :

# cat myfile
Bb2$£¤µ%§\°~`!@#$%^&*()_-+={[}]|:;"'<,>.?/
# sed...

If you consider using my proposal above, you can add any number of punctuation chars to be saved from removal. There may be some extra efforts needed to implement using a variable, but it should be...

try sth like this,,

sed -e 's/#/LOLOLOL/g;s/@/MOMOMO/g;s/\([[:punct:]]\)//g;s/LOLOLOL/#/g;s/MOMOMO/@/g;' file

Fiddling around with awks, sed, locales, and char classes I've come up with this, respecting locale's punctuation class, and allowing to keep any number of punct. chars:sed "s#[]\
$(
...

I must not understand what you're proposing to do here. If you start with a file that contains the punctuation characters comma and period (that you want to keep) and other punctuation characters...

Try changing:
cat ${a[$j]} | sed -e 's/\([[:punct:]]\)//g' > revised.txtto:
sed -e 's/#/^g/g;s/\([[:punct:]]\)//g;s/^g/#/g' "${a[$j]}" > revised.txtwhere the ^g in both cases is a control character...

Put them in exclude.txt and use grep -f -F.

for FILE in *.txt
do
sed 's/[^a-zA-Z \r\t]//g' "$FILE" |
tr -s ' \r\t' '\n' |
grep -v -F -f exclude.txt |...

I get this. $ ./fator.sh 1 2 3 4
1 2 3 4
No of arguments: 4
length of array is: 4
k[0] = 1
a[0] =
k[1] = 2
a[1] = 2
k[2] = 3
a[2] =
k[3] = 4
a[3] =

$ What am I supposed to be seeing...

I'd go about that in a slightly different way.

1) Strip out all non-alphanumeric and whitespace characters
2) Change all whitespace into newlines
3) Sort
4) uniq -c
5) Sort again to get the...

You can't use for [[ ... ]], can you? The requestor should use if / while [[ ... ]] to run the conditional branch.

It means what it says. (( )) brackets are used for arithmetic expressions. If you want to do things like comparing strings, use [[ ]].

[[ ${a[$i]} != "frn2c" ]]

Your problem was here:
a=("${a[$i]}" "$(fator ${k[$i]})")

Should be a=(${a[@]} "$(fator ${k[$i]})") ... or why not a[i]=$(fator ${k[i]})

Here is a bit of a cleanup to use bash expressions...