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Try ls *AN??[^E][^X]* *AN??E[^X]* *AN??[^E]X*

something like ls *|grep -v "$(ls ????_????_????_????OP_*.???)" but this is getting ridiculous, why not say exactly what you want : All the requisites and give ALL the information?

I don't understand.
$ ls -1
FORM_PTIR_9820_ANFDOP_20150716_00413561.DAT
FORM_PTIR_9820_ANFDOP_20150716_00413561.TXT
FORM_PTIR_9820_ANFDOP_20150716_00413562.DAT...

Instead of * which matches zero or more of any character, you could use ? to indicate a single character, so:-ls *Hello*.txt
ls ??????Hello???.txtThe first will match any files that has Hello...

You could also use the underscores as markers:
ls *_*_*OP_*.DAT
Although a bit less exact, it will probably get you what you want..

The unquoted glob-expression is evaluated by the shell, so you can as well do
echo ????_????_????OP_?????ls -1 (or ls if not seeing an interactive terminal) puts output line by line, that is...

ls FORM_[0-9][0-9][0-9][0-9]_[A-Z][A-Z][A-Z][A-Z]OP_?.DAT
or
ls FORM_[0-9][0-9][0-9][0-9]_[A-Z][A-Z][A-Z][A-Z]OP_[0-9].DAT

Hello,

the wildcard for a single character is ?, so your ls-command would look like this:
$ touch FORM_9757_TYUIOP_1.DAT FORM_9840_OPRTOP_2.DAT FORM_9757_TIRTOP_3.DAT
$ touch XOPX.DAT
$ touch...

# sed '1d;$d' file|awk 'BEGIN{printf "%10s%15s%15s\n","LNR","fcount","fcount(new)"}
{if(length($0)!=7)w="wrong number fo count";printf "%8s%12s%30s\n",NR+1,length($0),w;w=""}'
LNR ...

# cat file
xyz
a
ab
abc
abcd
abcde
abcdef
abcdefg
abcdefgh
123


# sed '1d;$d' file|awk 'BEGIN{printf "%s%10s\n","LNR","fcount"}{printf "%s%10s\n",NR+1,length($0)}' >newfile
LNR ...

I would recommend Bruce Blinn's "Portable shell programming, an extensive collection of bourne shell examples", along with Seebach's "Portable Shell Scripting: From Novice to Professional" and,...