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bash-3.2$ cat test.txt
abc,2,one,test
abc,3,one,test
abc,10,one,test
abc,5004,one,test
abc,100,one,test
abc,5004,one,test
abc,101,one,test
bash-3.2$ nawk -F, -v OFS=,...

for i in *.txt
do
awk -F, -v OFS=, '$2==2{$2=1;print $0}' $i > $i.out
mv $i.out $i
done

No, i think. Instead of giving *csv in awk. Use loop around your awk.

for files in *csv
do
awk '{print FILENAME;}' $files
done

do your options inside awk.
Cheers,
Ranga:-)

Hi,

Try this,


awk -F, -v OFS=, '$2==2{$2=1;a[NR]=$0;}END{for(i=1;i<=NR;i++){print a[i] >FILENAME;}}' input_file


FILENAME - give you the input file name.

Cheers,
Ranga:)

try my suggestion in the #4 post


$ sed 's/,\([0-9]*\),/,1010,/' input.txt
9788691010,1010,20120120002804,
9705645060,1010,20120120004753,
9014961516,1010,20120120004809,



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