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Try:
awk -F, '{for(i=1;i<=NF;i++)A[$i]=i;print "The field "v" is on position "A[v];delete A}' v=IDENTIFIER infile
or without arrays:
awk -F, '{for(i=1;i<=NF;i++)if($i==v)print "The field "v" is on...

perl -F, -lane'BEGIN {
$f = shift
}
$F[$_] eq $f
and print "The field $f is on position ", ++ $_
for 0 .. @F
' IDENTIFIER infile


---------- Post updated at 04:02 PM...

sed 's/.*,//;G;s/\n/&yes/' $FILE

awk -F"," '{print$5"\nyes"}' $FILE

If you really want to populate a shell array this should do it: I used awk to fetch field 5 and put quotes around it and then eval to assign array.

eval array=( $(awk -F, '{print "\""$5"\"";}'...

cut -f5 -d"," $FILE |while read line
do
echo $line
echo yes
done